Mysql 仅显示下一条记录上具有相同值的第一列

假设我有一张桌子

name ----------------------- phone ------------------------ address

Aldi ----------------------- 021345 ----------------------- Bogor

Aldi ------------------------021345 ----------------------- Jakarta

John ------------------------034566 ----------------------- Depok

如果第一列在下一条记录中具有相同的值，如何仅显示第一列？结果可能如下所示：

name ----------------------- phone ------------------------ address

Aldi ----------------------- 021345 ----------------------- Bogor

----------------------------------------------------------- Jakarta

John ----------------------- 034566 ----------------------- Depok

试试这个

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对你的表试试这个，把它粘贴成unicode代码块，听起来你需要一个报告工具。SQL将以表格格式返回数据。顺便说一下，我需要删除

。。。和t1.phone=t2.phone

select t1.id,
case when t1.name = t2.name and t1.phone = t2.phone
then
'-'
else
t1.name
end as name,
case when t1.name = t2.name and t1.phone = t2.phone
then
'-'
else
t1.phone
end as phone,t1.address from test t1 left join test t2 on t2.id = t1.id-1
order by t1.id