单个MySQL select语句中的“distinct count”和“distinct count if existing”

我有一个我已经发送的电子邮件表，以及我发送电子邮件的日期

-----------------------------
|   email   |   date_sent   |
-----------------------------
|  a@a.com  |  2013-01-10   | 
|  a@a.com  |  2013-01-10   |
|  a@a.com  |  2013-01-10   |
|  b@b.com  |  2013-01-10   |
|  a@a.com  |  2013-01-11   |
|  c@c.com  |  2013-01-11   |
-----------------------------

对于给定的日期，我需要获得发送的电子邮件总数、今天的唯一地址以及以前未出现的唯一地址

第一部分很简单：

SELECT count(email) emails_sent, count(distinct email) unique_users
from sent_emails where date_sent = '2013-01-10';

我很难收到以前没有出现过的电子邮件。可能吗

我尝试了许多不同的方法，但几乎没有成功。e、 g:

SELECT count(email) emails_sent, count(distinct email) unique_users,
sum( (select count(email) from sent_emails se
where se.date_sent < date_sent 
and se.email = email)) new_emailed_users
from sent_emails where date_sent = '2013-01-10';

这就是我对2013-01-11的预期结果：

--------------------------------------------------
| emails_sent | unique_users | new_emailed_users |
--------------------------------------------------
|      2      |      2       |         1         |
--------------------------------------------------

---

感谢您在没有子查询的情况下提供的帮助，提高了速度

select
count(if(date_sent='2013-01-10',email, null)) as emails,
count(distinct if(date_sent='2013-01-10',email, null)) as uniques,
count(distinct email) as total_unique_email
from sent_emails

---

这是我的解决办法。不确定它是最有效的：

SELECT count(email) emails_sent, count(distinct email) unique_users,
count(distinct if(not exists(select 1 from sent_emails where  date_sent < se.date_sent and se.email = email ),email,null)) new_emailed_users
from sent_emails se where date_sent = '2013-01-10';

SELECT count(email) emails_sent, count(distinct email) unique_users,
count(distinct if(not exists(select 1 from sent_emails where  date_sent < se.date_sent and se.email = email ),email,null)) new_emailed_users
from sent_emails se where date_sent = '2013-01-10';