Mysql 计算过期的&；每个唯一id的未过期行

我有一张这样的桌子：

| id      | certificate|expires   |
|       1 |        123 |12-DEC-15 | 
|       1 |        123 |12-DEC-09 |
|       1 |        123 |13-DEC-09 |
|       2 |        456 |14-DEC-16 |
|       2 |        456 |14-DEC-09 |
|       2 |        789 |14-DEC-09 |
|       2 |        789 |14-DEC-09 |

 |id | expired | unexpired |
 |1  |2        |1          |
 |2  |3        |1          |

我尝试对每个用户已过期和未过期的证书数量进行求和，如下所示：

| id      | certificate|expires   |
|       1 |        123 |12-DEC-15 | 
|       1 |        123 |12-DEC-09 |
|       1 |        123 |13-DEC-09 |
|       2 |        456 |14-DEC-16 |
|       2 |        456 |14-DEC-09 |
|       2 |        789 |14-DEC-09 |
|       2 |        789 |14-DEC-09 |

 |id | expired | unexpired |
 |1  |2        |1          |
 |2  |3        |1          |

我已经统计了所有过期的证书，但它只显示了未过期的行数。如何获取过期证书的数量

   SELECT 
      id, 
      COUNT(certificate) as numcerts, 
      expires
   FROM 
     certificates
   WHERE 
     expires > current_date()
  GROUP BY id
  having numcerts > 0
  ORDER BY COUNT(*) DESC

---

如果日期存储在

date

数据类型中，则下面的查询将给出结果

select 
id, 
sum( case when expires < curdate() then 1 else 0 end ) as expires,
sum( case when expires > curdate() then 1 else 0 end ) as unsepired 
from certificates group by id 

---

您通过

expires>current\u date（）

使用STR\u TO\u date将这些文本明确筛选出来，以将其转换为正确的日期。非常感谢。这个答案非常完美。