MySQL中日期字段中的“按年分组”

我有一个MySQL数据库，它有一个客户表。一些虚拟数据是：

customer_id    date
000001         2008-10-10
000002         2008-11-11
000003         2010-01-02
000004         2007-04-03
000005         2010-05-05

我想运行一个查询，结果如下：

year    customer_count
2007    1
2008    2
2010    2

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我知道我需要使用group by，但是我无法理解如何根据日期字段的年份值进行分组，以及如何将它们按顺序排列。

从日期中提取年份并按日期分组

select year(date) as year, 
       count(customer_id) as customers
from your_table
group by year
order by year asc

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从日期中提取年份并按其分组

select year(date) as year, 
       count(customer_id) as customers
from your_table
group by year
order by year asc

使用函数获取日期的年份部分，并在分组和排序中使用该部分

SELECT YEAR(date) AS year, COUNT(*) AS customer_count
FROM customer
GROUP BY year
ORDER BY year

使用函数获取日期的年份部分，并在分组和排序中使用该部分

SELECT YEAR(date) AS year, COUNT(*) AS customer_count
FROM customer
GROUP BY year
ORDER BY year

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使用

提取

功能获取日期的相关部分：

select extract(YEAR from join_d)"Year",count(DISTINCT customer_id) "customer_count" 
from  customer 
group by year
order by year;

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使用

提取

功能获取日期的相关部分：

select extract(YEAR from join_d)"Year",count(DISTINCT customer_id) "customer_count" 
from  customer 
group by year
order by year;