Mysql Django:保存到数据库connundrun

我认为以下几点非常有效：

if request.method == 'POST':

form = SelectTwoTeams(request.POST,user=request.user)

if form.is_valid():

    teamSelection1 = UserSelection(campaignno = 102501350,
                  teamselection1or2 = 1,
                                  teamselectionid_id = request.POST['team1'],
                                  user_id=currentUserID,
                                  fixturematchday=fixturematchday,
                                  soccerseason_id=soccerseason)
    teamSelection1.save()

    teamSelection2 = UserSelection(campaignno = 102501350,
                                   teamselection1or2 = 2,
                                   teamselectionid_id = request.POST['team2'],
                                   user_id=currentUserID,
                                   fixturematchday=fixturematchday,
                                   soccerseason_id=soccerseason)
    teamSelection2.save()

当代码运行时，它会很好地在我的数据库中结束，因为它应该：

mysql> select * from straightred_userselection;
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
| userselectionid | campaignno | teamselection1or2 | teamselectionid | user_id | fixturematchday | soccerseasonid |
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
|               9 |  102501350 |                 1 |               6 |     349 |               2 |           1025 |
|              10 |  102501350 |                 2 |               7 |     349 |               2 |           1025 |
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
2 rows in set (0.00 sec)

但是，让我们假设我现在想要选择两个不同的团队（目前在teamselectionid列下为6和7）。我可以在表单中选择它们并进行更新，但是当代码运行时，它只会向表中添加另外两行，而不是更新当前的行。检查是否需要更新的一组新团队选择，只需满足以下条件：

• fixturematchday和soccerseasonid随后相同，然后更新
• fixturematchday和soccerseasonid不相同，然后创建新条目

如上所述，它目前只添加了两个新行，如下所示：

mysql> select * from straightred_userselection;
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
| userselectionid | campaignno | teamselection1or2 | teamselectionid | user_id | fixturematchday | soccerseasonid |
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
|               9 |  102501350 |                 1 |               6 |     349 |               2 |           1025 |
|              10 |  102501350 |                 2 |               7 |     349 |               2 |           1025 |
|              11 |  102501350 |                 1 |               9 |     349 |               2 |           1025 |
|              12 |  102501350 |                 2 |              14 |     349 |               2 |           1025 |
+-----------------+------------+-------------------+-----------------+---------+-----------------+----------------+
4 rows in set (0.00 sec)

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非常感谢您的帮助，艾伦。

这是因为您每次都在创建新对象。改用update\u或create:

让我解释一下有关update\u或create的更多信息，在您的情况下，您需要的是如果teamselectionid存在，只需更新该对象即可。因此应该

obj, created = UserSelection.objects.update_or_create(
teamselectionid=teamselectionid, defaults=what_field_you_want_to_update)

编辑 默认值之前的参数只允许您在数据库中查找唯一行，例如，一个用户可以选择多个团队，因此仅使用用户id无法找到唯一行，但您可以将用户id和团队id组合在一起，如：

obj, created = UserSelection.objects.update_or_create(
    user_id=user_id, team_id=team_id, defaults=what_field_you_want_to_update)

---

抱歉，我刚刚意识到如果teamselectionid不存在，则不是这样。会有很多人选择了这个团队。仅当用户id、fixturematchday和seasonid存在时才可用。希望这有意义？