具有多个条件的Mysql查询

我必须得到多个类别的产品（Prestashop数据库）

这是我的问题：

SELECT COUNT( cp.`id_product` ) AS total
FROM  `ps_product` p
INNER JOIN ps_product_shop product_shop ON ( product_shop.id_product = p.id_product
AND product_shop.id_shop =1 ) 
LEFT JOIN  `ps_category_product` cp ON p.`id_product` = cp.`id_product` 
WHERE cp.`id_category` =6
AND cp.`id_category` =126
AND product_shop.`visibility` 
IN (
"both",  "catalog"
)
AND product_shop.`active` =1

我想选择内部类别6和内部类别126，但我的查询返回0

一个产品可以有多个类别，因此我只想在两个类别中选择产品

如何解决这个问题，使我得到预期的结果？

使用

WHERE cp.`id_category` =6
OR cp.`id_category` =126

朋友，试试这个

SELECT COUNT( cp.id_product ) AS total
FROM  ps_product p
Left JOIN ps_product_shop product_shop ON ( product_shop.id_product = p.id_product
                                            AND product_shop.id_shop =1 ) 
LEFT JOIN  ps_category_product cp ON p.id_product = cp.id_product 
            and cp.id_category in(6)
LEFT JOIN  ps_category_product cp1 ON p.id_product = cp1.id_product 
            and cp1.id_category in(126)
WHERE cp.id_category is not null
    and cp1.id_category is not null
    AND product_shop.visibility IN ('both',  'catalog')
    AND product_shop.active =1

---

你是说6到126之间？无法针对6和126的一列进行验证。如果介于两者之间，则使用

SELECT COUNT( cp.`id_product` ) AS total
FROM  `ps_product` p
INNER JOIN ps_product_shop product_shop ON ( product_shop.id_product = p.id_product
AND product_shop.id_shop =1 ) 
LEFT JOIN  `ps_category_product` cp ON p.`id_product` = cp.`id_product` 
WHERE cp.`id_category` between 6 and 126
AND product_shop.`visibility` 
IN (
"both",  "catalog"
)
AND product_shop.`active` =1

在这两个类别中：

SELECT COUNT( cp.id_product ) AS total
FROM  ps_product p
Left JOIN ps_product_shop product_shop ON (product_shop.id_product = p.id_product
                                           AND product_shop.id_shop = 1)     
WHERE product_shop.visibility IN ('both',  'catalog')
  AND product_shop.active = 1
  AND EXISTS(SELECT * FROM ps_category_product cp 
             WHERE p.id_product = cp.id_product AND cp.id_category = 6)
  AND EXISTS(SELECT * FROM ps_category_product cp 
             WHERE p.id_product = cp.id_product AND cp.id_category = 12)

---

不是那样。我只想要这些类别的产品，不是全部在第6类和第126类内部。它返回第6类和第126类中的产品，但不是仅在这两个类别中的产品。内部是什么意思？请举例说明。我有两种产品属于第6类。我有3种126类产品。只有一个产品有类别6和126，所以，我只想要一个结果！所以你们想要产品，这在两个类别中都有？仍然在寻找最好的选择。而不是cp.id_category=6和cp.id_category=126。在（6126）中使用cp.id_类别。检查下面的完整代码。不使用内部连接，仅在类别6和126中使用左连接编号

WHERE (cp.`id_category` = 6 OR cp.`id_category` = 126)
AND product_shop.`visibility` IN ("both",  "catalog")
AND product_shop.`active` = 1

SELECT COUNT( cp.id_product ) AS total
FROM  ps_product p
Left JOIN ps_product_shop product_shop ON (product_shop.id_product = p.id_product
                                           AND product_shop.id_shop = 1)     
WHERE product_shop.visibility IN ('both',  'catalog')
  AND product_shop.active = 1
  AND EXISTS(SELECT * FROM ps_category_product cp 
             WHERE p.id_product = cp.id_product AND cp.id_category = 6)
  AND EXISTS(SELECT * FROM ps_category_product cp 
             WHERE p.id_product = cp.id_product AND cp.id_category = 12)