Mysql 连接多个表时出现问题

我有四张桌子：

products sizes 这是我的SQL代码：

SELECT   DISTINCT products.product_name, sizes.pizza_size_name 
FROM     products, menu_details, pizza_menus, sizes 
WHERE    products.product_id = menu_details.products_fk 
AND      menu_details.pizza_menus_fk = pizza_menus.menu_id 
AND      pizza_menus.size_id = sizes.pizza_size_id 
AND      menu_details.order_details_fk = 132

我的期望输出

----------------------------------
| product_name | pizza_size_name |
----------------------------------
|    Italyan   |      Small      |
|    Classic   |      Small      |
|    Lamb      |      Small      |
|    Evi       |      Medium     |
----------------------------------

我得到的输出

----------------------------------
| product_name | pizza_size_name |
----------------------------------
|    Italyan   |      Small      |
|    Classic   |      Small      |
|    Lamb      |      Small      |
|    Evi       |      Small      |
|    Italyan   |      Medium     |
|    Classic   |      Medium     |
|    Lamb      |      Medium     |
|    Evi       |      Medium     |
----------------------------------

对于这样简单的问题，我知道的表格太多了，但无论如何

---

我真的很感谢你的帮助，谢谢

菜单详情和比萨饼菜单之间的关联错误，因此我将菜单详情更改为：

--------------------------------------------------------
| id | order_details_fk | pizza_menus_fk | products_fk |
--------------------------------------------------------
| 17 |        132       |       25       |     39      |
| 18 |        132       |       26       |     40      |
| 19 |        132       |       27       |     41      |
| 20 |        132       |       28       |     42      |
--------------------------------------------------------

下面是我的新SQL：

SELECT   DISTINCT products.product_name, sizes.pizza_size_name 
FROM     products, menu_details, pizza_menus, sizes 
WHERE    products.product_id = menu_details.products_fk 
AND      menu_details.pizza_menus_fk = pizza_menus.id 
AND      pizza_menus.size_id = sizes.pizza_size_id 
AND      menu_details.order_details_fk = 132

---

外键通常应引用另一个表的唯一键。为什么

pizza\u menu\u fk

指的是

pizza\u menu.id

而不是

pizza\u menu.id

？得到这个结果的原因是

menu\u id=92

既有

size\u id=1

又有

size\u id=2

。因此，所有带有比萨饼菜单的

菜单详细信息

都有两种尺寸。如果您使用

id

而不是

menu\u id

作为外键，那么您可以指向

pizza\u menu

中的特定行，只获得一个大小。@Barmar-是的，先生。那是我的错误。非常感谢。@AbdulAzizNurov，请将答案添加为答案，而不是在问题中发布答案；这样，你就可以用问答的方式分享你的解决方案（这就是全部）：@Barranka谢谢你的提示。这是我的第一次经历，所以我不知道我能回答我自己的问题：D

SELECT   DISTINCT products.product_name, sizes.pizza_size_name 
FROM     products, menu_details, pizza_menus, sizes 
WHERE    products.product_id = menu_details.products_fk 
AND      menu_details.pizza_menus_fk = pizza_menus.menu_id 
AND      pizza_menus.size_id = sizes.pizza_size_id 
AND      menu_details.order_details_fk = 132

----------------------------------
| product_name | pizza_size_name |
----------------------------------
|    Italyan   |      Small      |
|    Classic   |      Small      |
|    Lamb      |      Small      |
|    Evi       |      Medium     |
----------------------------------

----------------------------------
| product_name | pizza_size_name |
----------------------------------
|    Italyan   |      Small      |
|    Classic   |      Small      |
|    Lamb      |      Small      |
|    Evi       |      Small      |
|    Italyan   |      Medium     |
|    Classic   |      Medium     |
|    Lamb      |      Medium     |
|    Evi       |      Medium     |
----------------------------------

--------------------------------------------------------
| id | order_details_fk | pizza_menus_fk | products_fk |
--------------------------------------------------------
| 17 |        132       |       25       |     39      |
| 18 |        132       |       26       |     40      |
| 19 |        132       |       27       |     41      |
| 20 |        132       |       28       |     42      |
--------------------------------------------------------

SELECT   DISTINCT products.product_name, sizes.pizza_size_name 
FROM     products, menu_details, pizza_menus, sizes 
WHERE    products.product_id = menu_details.products_fk 
AND      menu_details.pizza_menus_fk = pizza_menus.id 
AND      pizza_menus.size_id = sizes.pizza_size_id 
AND      menu_details.order_details_fk = 132