Mysql 如何根据销售目标确定员工奖金？

我需要找到那些达到销售目标的员工的身份证，并根据他们的销售目标确定他们每个人应该获得多少奖金

create table ta(
empid int(10),
sales int(10)
);

empid  - sales
101    - 9898
201    - 988
301    - 87988
401    - 88
501    - 202088

 create table tb(
 target int(10),
 bonus varchar(100));

Target  - Bonus
1000    - 25%
5000    - 50%
10000   - 70%
50000   - 85%
100000  - 100%

================================= 我试过了

select ta.*
from   ta
    right outer join tb on ta.sales=tb.target
where sales <= bonus;

选择ta*
来自助教
右外部连接ta上的tb.sales=tb.target
在销售中，您可以使用
分组方式使用以下解决方案：

SELECT ta.empid, ta.sales, MAX(tb.target) AS target, CONCAT(MAX(REPLACE(tb.bonus, '%', '') + 0), '%') AS bonus
FROM ta LEFT JOIN tb ON tb.target <= ta.sales
GROUP BY ta.empid, ta.sales
ORDER BY ta.empid

首先获取员工已实现的所有目标，然后获取最高目标：

select t.empid, t.target, tb.bonus from (
  select empid, max(target) target
  from (
    select *
    from ta inner join tb
    on tb.target <= ta.sales
  ) g 
  group by empid  
) t inner join tb on tb.target = t.target 

两个表中相同的[primary->foreign]列在哪里进行联接？给定的查询有什么问题？“我需要为那些达到销售目标的员工查找员工ID，并根据他们的销售目标确定每个人应该获得多少奖金。”我的意思是，预期的结果是什么？您应该创建一个预期的输出结果集。
SELECT ta.empid, ta.sales, MAX(tb.target) AS target, CONCAT(MAX(REPLACE(tb.bonus, '%', '') + 0), '%') AS bonus
FROM ta LEFT JOIN tb ON tb.target <= ta.sales
GROUP BY ta.empid, ta.sales
HAVING MAX(tb.target) IS NOT NULL -- or just using INNER JOIN
ORDER BY ta.empid

select t.empid, t.target, tb.bonus from (
  select empid, max(target) target
  from (
    select *
    from ta inner join tb
    on tb.target <= ta.sales
  ) g 
  group by empid  
) t inner join tb on tb.target = t.target 

| empid | target | bonus |
| ----- | ------ | ----- |
| 101   | 5000   | 50%   |
| 301   | 50000  | 85%   |
| 501   | 100000 | 100%  |