从MySQL获取分层数据

我有两张桌子。球队和球员。我想做的是创建一个查询，告诉我一些关于最大团队工资的统计数据。具体来说，我想统计一下有多少球员的收入低于5公里。有多少人在5公里和10公里之间……以5公里为增量，达到最大玩家

以下是SQL：

CREATE  TABLE `formsfiles`.`Teams` (
  `ID` INT NOT NULL AUTO_INCREMENT ,
  `Name` VARCHAR(45) NULL ,
  PRIMARY KEY (`ID`) );


INSERT INTO `Teams` (`Name`) VALUES ('Sharks');
INSERT INTO `Teams` (`Name`) VALUES ('Jets');
INSERT INTO `Teams` (`Name`) VALUES ('Fish');
INSERT INTO `Teams` (`Name`) VALUES ('Dodgers');


CREATE  TABLE `Players` (
  `ID` INT NOT NULL AUTO_INCREMENT ,
  `Name` VARCHAR(45) NULL ,
  `Team_ID` INT NULL ,
  `Salary` INT NUll ,
  PRIMARY KEY (`ID`) );

INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Jim', '1', '4800');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Tom', '1', '12000');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Harry', '2', '1230');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Dave', '2', '19870');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Tim', '3', '1540');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Trey', '4','7340');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Jay', '4', '4800');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Steve', '4','6610');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Chris', '4','17754'); 

根据这些数据：道奇队是最大的队ID=4 我们希望输出：

0-5000       1
5000-10000   2
10000-15000  0
15000-20000  1

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如果这段代码看起来很熟悉，那是因为它是我在这里发布的前一个问题的演化。请不要把我打倒

以下是我的尝试。它使用联接来满足以下条件：

select sr.range,
       SUM(case when p.salary >= sr.low and p.salary < sr.high then 1 else 0 end)          
from Players p join
     (select t.id
      from Players p join
           Teams t
           on p.team_id = t.id
      group by t.team_id
      order by SUM(p.salary) desc
      limit 1
     ) team
     on p.team_id = team.id cross join
     (select '0-5000' as range, 0 as low, 5000 as high union all
      select '5000-10000', 5000, 10000 union all
      select '10000-15000', 10000, 15000 union all
      select '15000-20000', 15000, 20000
     ) sr
group by sr.range
order by min(sr.low)

---

请注意，对范围使用了单独的查询，以确保得到的行数为0。

此代码几乎可以满足您的需要

SELECT 5000 * FLOOR(Salary / 5000), count(*)
FROM Players 
WHERE Team_ID = 4
GROUP BY FLOOR(Salary / 5000)

它返回范围的下限和条目数

0        1
5000     2
15000    1

---

请注意，它不会返回空范围。

您可以使用简单的中间条件选择它们并将它们合并