mysql强制结果的顺序与IN子句的顺序匹配

这个问题与关于按IN子句排序最终结果的问题不同

我想强制包含IN子句的查询返回的结果与IN子句的顺序匹配

我工作的地方

我想修改下面的查询，以便在按日期时间排序表单页面点击表时，在每个会话id的progress=4和progress=7之前出现包含progress=2的行

以下是当前查询：

SELECT  COUNT(*)
FROM    (
    SELECT  session_id
    FROM    formation_page_hits
    WHERE   progress IN (2, 4, 7)
            AND datetime >= '2011-03-23'
            AND datetime < '2011-03-24'
    GROUP BY
            session_id
    HAVING  COUNT(DISTINCT progress) = 3
    ) q

应与查询匹配，但：

datetime,               session_id, progress
('2011-03-01 01:02:11', 'abc',      4)
('2011-03-01 01:02:12', 'abc',      2)
('2011-03-01 01:02:13', 'abc',      7)

不应该是一场比赛

此外：

datetime,               session_id, progress
('2011-03-01 01:02:11', 'abc',      4)
('2011-03-01 01:02:12', 'abc',      2)
('2011-03-01 01:02:13', 'abc',      4)
('2011-03-01 01:02:14', 'abc',      7)

---

应该是匹配的。

更常见的方法是在升序日期时间使用双重自联接，以三向联接结束。然而，这并不是一个性能良好的查询

select *
from
(
    SELECT  session_id, group_concat(concat('|',progress,'/') order by datetime) list
    FROM    formation_page_hits
    WHERE   progress IN (2, 4, 7)
            AND datetime >= '2011-03-23'
            AND datetime < '2011-03-24'
    GROUP BY session_id
    HAVING  COUNT(DISTINCT progress) = 3
) X
where list like '%|2/%|4/%|7/%'

---

2，4，7是严格的升序。您的示例数据是特殊的还是希望始终使用升序？

select *
from
(
    SELECT  session_id, group_concat(concat('|',progress,'/') order by datetime) list
    FROM    formation_page_hits
    WHERE   progress IN (2, 4, 7)
            AND datetime >= '2011-03-23'
            AND datetime < '2011-03-24'
    GROUP BY session_id
    HAVING  COUNT(DISTINCT progress) = 3
) X
where list like '%|2/%|4/%|7/%'