Mysql THE where子句，但它似乎不起作用。此查询非常有效。谢谢你，巴德。然而，出于好奇，我试图通过普通的join with where子句执行相同的查询，但似乎不起作用。谢谢你，巴德。然而，出于好奇，我试图通过普通的join with where子句执行相

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THE where子句，但它似乎不起作用。此查询非常有效。谢谢你，巴德。然而，出于好奇，我试图通过普通的join with where子句执行相同的查询，但似乎不起作用。谢谢你，巴德。然而，出于好奇，我试图通过普通的join with where子句执行相同的查询，但似乎不起作用。谢谢你，巴德。然而，出于好奇，我试图通过where子句的正常连接执行相同的查询，但似乎不起作用？无论哪种方式，这个查询都会返回缺少的SET关键字errorAFAIK多个表不能在update语句中使用？无论哪种方式，这个查询都会返回缺少的SET关键字errorAFAIK多个表不能在update语句中使用？无论哪种方式，这个查询都会返回缺少的SET关键字errorAFAIK多个表不能在update语句中使用？无论哪种方式，此查询都会返回缺少的SET关键字错误

give 10% bonus on total salary to the employees who are not in IT departments. 

update salary_paid 
set bonus=(select (0.1*total_salary) "Bonus" 
           from salary_paid, departments, employees
           where 
               employees.department_id=departments.department_id and 
               employees.employee_id=salary_paid.employee_id and
               departments.department_name!='IT')
           ;

   UPDATE 
    (SELECT salary_paid.bonus as oldBonus, 0.1*salary_paid.total_salary as newBounus
     FROM salary_paid
     INNER JOIN employees
     ON salary_paid.employee_id = employees.employee_id
     INNER JOIN departments
     ON departments.department_id = employees.department_id 
     WHERE departments.department_name != 'IT'
    ) t
    SET t.oldBonus= t.newBounus

UPDATE
    (
        SELECT *
        FROM employees e LEFT JOIN salary_paid sp ON e.employee_id = sp.employee_id
            LEFT JOIN departments d ON d.department_id = e.department_id
    ) t
SET t.bonus = 0.1 * t.total_salary
WHERE t.department_name != 'IT';

select (0.1*total_salary) "Bonus" from salary_paid, departments, employees
where employees.department_id=departments.department_id and employees.employee_id=salary_paid.employee_id and departments.department_name!='IT'

select (0.1*total_salary) "Bonus" from salary_paid, departments, employees
where employees.department_id=departments.department_id and employees.employee_id=salary_paid.employee_id and departments.department_name!='IT' limit 0,1

update salary_paid a,departments b, employees c set a.bonus=(0.1*a.total_salary) "Bonus" 
where c.department_id=b.department_id and c.employee_id=a.employee_id and b.department_name!='IT';

update (select email as oldemail, substr(first_name,1,1)||''||last_name||''||'@gmail.com' as email from employees
inner join departments
on
employees.department_id= departments.department_id
)t
set t.oldemail=t.email