Mysql比较两个表

Mysql比较两个表,mysql,Mysql,如何比较不同表中的三个值 pm_meta +----+----------+--------+----------+ | id | item_id |meta_key|meta_value| +----+----------+--------+----------+ | 2 | 100 | google |googl.com | | 3 | 101 | yahoo |yahoo.com | | 3 |

如何比较不同表中的三个值

    pm_meta
    +----+----------+--------+----------+
    | id | item_id  |meta_key|meta_value|
    +----+----------+--------+----------+
    |  2 |     100  | google |googl.com |
    |  3 |     101  | yahoo  |yahoo.com |
    |  3 |     102  | msn    |msn.com   |
    +----+----------+--------+----------+

    pm_embed_code
    +------+-----------+------------+
    | id   | uniq_id   |embed_code  |
    +------+-----------+------------+
    |  100 |     abcd  |<iframe src=|
    |  101 |     dddc  |<iframe src=|
    |  102 |     ffdd  |<iframe src=|
    +----+----------+------------+



    $sql = "SELECT * 
            FROM pm_embed_code, pm_meta
            WHERE pm_embed_code.uniq_id = 'abcd'
            AND pm_embed_code.id = pm_meta.item_id
            AND pm_meta.meta_key = 'google' ";

    echo $row['meta_value']; // I want result "googl.com"
这一个也没有显示任何。。。为什么?

使用连接:

Select * from  pm_embed_code join pm_meta on pm_emped_code.id=m_meta.item_id
where pm_embed_code.uniq_id = 'abcd' AND  pm_meta.meta_key = 'google'

您收到的错误消息。查询看起来是正确的

$sql = "SELECT pm.meta_value 
        FROM pm_embed_code pec, pm_meta pm
        WHERE pec.id = pm.item_id
        AND pec.uniq_id = 'abcd'
        AND pm.meta_key = 'google' ";

echo $row['meta_value'];
查询:

选择pm.id为“pm\u embed\u code.id”,pm.meta\u key为“pm\u meta.meta\u key”,从pm\u meta pm左侧外部加入pm\u embed\u code pmc ON pmc.id=pm.item\u id,其中pmc.uniq\u id=“abcd”和pm.meta\u key='google'

代码

$sql=“选择pm.id作为“pm\u embed\u code.id”,pm.meta\u key作为“pm\u meta.meta\u key”,从pm\u meta pm左侧外部加入pm\u embed\u code pmc ON pmc.id=pm.item\u id,其中pm.uniq\u id=“abcd”和pm.meta\u key='google'”


echo$row[“pm_meta.meta_key”]

空结果,如果启用mysql错误我得到结果“1”,我很惊讶pm_meta.id不是唯一的,而item_id是!?!
        SELECT pm_embed_code.* , pm_meta.*
        FROM pm_embed_code
        INNER JOIN pm_meta
        ON pm_embed_code.id = pm_meta.item_id
          AND pm_meta.meta_key = 'google' 
        WHERE pm_embed_code.uniq_id = 'abcd'
$sql = "SELECT pm.meta_value 
        FROM pm_embed_code pec, pm_meta pm
        WHERE pec.id = pm.item_id
        AND pec.uniq_id = 'abcd'
        AND pm.meta_key = 'google' ";

echo $row['meta_value'];