Mysql 如何根据其他表列选择列？

我有两张桌子：表一和表二。 两个表如下所示：

这是表1

这是表2

现在我想根据table2.t1_ID获得table1.title，如AAA、BBB、CCC，如下所示：

+----+----------+-----------+
| id | t2_title | t1_titles |
+----+----------+-----------+
| 1  | John     | AAA,CCC   |
+----+----------+-----------+
| 2  | Sam      | BBB       |
+----+----------+-----------+
| 3  | Monty    | AAA,BBB   |
+----+----------+-----------+
| 4  | Rose     | BBB,CCC   |
+----+----------+-----------+

---

修正你的数据模型！ID不应存储在字符串列表中。数字不应存储为字符串。应该正确声明外键关系！要做的第一件事是不要设计一个将ID以逗号分隔的列表形式存储到另一个表的表。您需要一个数据透视表来创建多对多关系。

+----+----------+--------+
| id | t2_title | t1_IDs |
+----+----------+--------+
| 1  | John     | 1,3    |
+----+----------+--------+
| 2  | Sam      | 2      |
+----+----------+--------+
| 3  | Monty    | 1,2    |
+----+----------+--------+
| 4  | Rose     | 2,3    |
+----+----------+--------+

+----+----------+-----------+
| id | t2_title | t1_titles |
+----+----------+-----------+
| 1  | John     | AAA,CCC   |
+----+----------+-----------+
| 2  | Sam      | BBB       |
+----+----------+-----------+
| 3  | Monty    | AAA,BBB   |
+----+----------+-----------+
| 4  | Rose     | BBB,CCC   |
+----+----------+-----------+

SELECT  a.id,
        t2_title,
        GROUP_CONCAT(b.t1_title ORDER BY b.id)
FROM    table2 a
        INNER JOIN table1 b
            ON FIND_IN_SET(b.t1_title, a.t1_IDs) > 0
GROUP   BY a.id,a.t2_title