Mysql SQL-如果同一记录不在表Y中，则从表X中删除该记录

很抱歉再次对删除相同的记录大惊小怪，但我找不到任何解决方案：（

我需要这样的东西：

如果从表1中选择3列值
不等于表2中的相同选择
然后从表2中删除记录

这是我的便签：

DELETE FROM table2
INNER JOIN table1
ON table2.basketid = table1.basketid AND
table2.artid = table1.artid
WHERE table1.userid='007'

DELETE FROM table2
WHERE NOT EXISTS (
SELECT basketid, artid
FROM table1
)
AND userid ='007'

感谢您的帮助或任何提示！！

您可能需要where（）而不是in（）

---

您可以在SQL Server中执行此操作

DELETE  t2
FROM    Table2 t2
WHERE   NOT EXISTS ( SELECT 1
                     FROM   Table1 t1
                     WHERE  t1.basketid = t2.basketid
                            AND t1.artid = t2.artid )
        AND t2.userid = '007'

注意select中比较表2和表1中的值的过滤器

如果userid也在表2中，您可能希望将其添加到WHERE-allow中

DELETE  t2
FROM    Table2 t2
WHERE   NOT EXISTS ( SELECT 1
                     FROM   Table1 t1
                     WHERE  t1.userid = t2.userid
                            AND t1.basketid = t2.basketid
                            AND t1.artid = t2.artid )
        AND t2.userid = '007'

---

请尝试上面的代码。

这是sql server的问题吗？

DELETE  t2
FROM    Table2 t2
WHERE   NOT EXISTS ( SELECT 1
                     FROM   Table1 t1
                     WHERE  t1.userid = t2.userid
                            AND t1.basketid = t2.basketid
                            AND t1.artid = t2.artid )
        AND t2.userid = '007'

DELETE y
FROM  X
LEFT JOIN Y
ON 
    X.COL1=Y.COL1
AND
    X.COL2=Y.COL2
AND
    X.COL3=Y.COL3
WHERE 
    Y.COL1 IS NULL