MySQL查询联接以从两个表中选择不匹配的行
我有两张桌子,如下所示MySQL查询联接以从两个表中选择不匹配的行,mysql,sql,join,mysql5,Mysql,Sql,Join,Mysql5,我有两张桌子,如下所示 我试过这个问题 SELECT users.* FROM users WHERE users.username NOT IN( SELECT users_approval.username FROM users_approval WHERE users_approval.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7" ) AND users.role_type = "student" 得
我试过这个问题
SELECT users.* FROM users
WHERE users.username NOT IN(
SELECT users_approval.username FROM users_approval
WHERE users_approval.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
) AND users.role_type = "student"
得到了下面的结果
是否有任何方法可以使用JOIN获取与上述相同的结果集 我很感激你的帮助
SELECT users.*
FROM users
LEFT JOIN users_approval b
ON users.username = b.username AND
b.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
WHERE users.role_type = "student" AND
b.approved_id IS NULL
假设您在第二个表中有user_id作为外键,它可以用来连接,而不是使用username来连接表awesome。。!我现在对连接的工作方式有了一些想法:P。非常感谢
SELECT users.* FROM users
WHERE users.username NOT IN(
SELECT users_approval.username FROM users_approval
WHERE users_approval.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
) AND users.role_type = "student"
user_id | username | first_name | role_type
-------------------------------------------------------------
4 | testuser4 | testu4 | student
5 | testuser5 | testu5 | student
-------------------------------------------------------------
SELECT users.*
FROM users
LEFT JOIN users_approval b
ON users.username = b.username AND
b.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
WHERE users.role_type = "student" AND
b.approved_id IS NULL
SELECT
users.*
FROM users as u
LEFT JOIN users_approval as ua ON ua.id = u.id
WHERE u.role_type = "student" AND ua.approved_id IS NULL