Mysql 使用3个表按2个值排序

抱歉，如果这是一个愚蠢的问题，我搜索了一点，找不到像我这样的例子的解决方案

我有一个小的照片共享应用程序，其中有一个查询，可以输出用户的ID号，按用户拥有的追随者数量排序。我想稍微修改一下查询，这样如果用户拥有相同数量的关注者，他们将按照上传的照片数量进行排序

我将如何编辑我的查询？我所有的尝试都没有成功

当前查询如下所示：

SELECT Users.ID, COUNT(User_Followers.FollowingUserID)
               AS follower_count FROM Users
               LEFT JOIN User_Followers ON Users.ID = User_Followers.FollowingUserID
               GROUP BY Users.ID
               ORDER BY follower_count DESC

ID     UserID     FollowingUserID    DateFollowed

ID     PostedByUserID     DatePosted

其中User_Followers表如下所示：

SELECT Users.ID, COUNT(User_Followers.FollowingUserID)
               AS follower_count FROM Users
               LEFT JOIN User_Followers ON Users.ID = User_Followers.FollowingUserID
               GROUP BY Users.ID
               ORDER BY follower_count DESC

ID     UserID     FollowingUserID    DateFollowed

ID     PostedByUserID     DatePosted

照片表如下所示：

SELECT Users.ID, COUNT(User_Followers.FollowingUserID)
               AS follower_count FROM Users
               LEFT JOIN User_Followers ON Users.ID = User_Followers.FollowingUserID
               GROUP BY Users.ID
               ORDER BY follower_count DESC

ID     UserID     FollowingUserID    DateFollowed

ID     PostedByUserID     DatePosted

---

提前感谢您的帮助

您的问题是什么？非常感谢！如果我想检查输出（例如在PHPMyAdmin中），我将如何修改它以显示第三列，显示每个用户的照片数？

选择Users.ID，COUNT（user\u Followers.followeruserid）作为Followers\u COUNT，a.postCount FROM…

再次感谢您的帮助！正如你可能已经猜到的，MySQL不是我的专长：P

SELECT  Users.ID,   
        COUNT(User_Followers.FollowingUserID) AS follower_count 
FROM    Users
        LEFT JOIN User_Followers 
            ON Users.ID = User_Followers.FollowingUserID
        LEFT JOIN
        (
            SELECT PostedByUserID, COUNT(*) postCount
            FROM photos
            GROUP BY PostedByUserID
        ) a ON Users.ID = a.PostedByUserID
GROUP BY Users.ID
ORDER BY follower_count DESC, a.postCount DESC