Mysql 列匹配的累积和

我想做一个查询，给我一个所有星期的累计总数，但以新月形的顺序显示它们，如

Person | Week 1 | Week2 = Week1 + Week2 | Week 3 = Week 1 + 2 + 3|

我的桌子像

ID | Week | Person | Item 1 | Item 2 | Item 3 | Iteration

一周的结果是所有项目的总和，迭代次数应该是该周的最高次数

到目前为止，我已经得出了这个结论，但结果不是预期的，因为所有行的周1总和都相等，这是错误的

SELECT person, w1sum, w2sum
FROM table AS t1, (

SELECT SUM( item1 + item2 + item3 ) AS w1sum
FROM table 
WHERE week =1
AND iteration
IN (

SELECT MAX( iteration ) 
FROM table
)
    GROUP BY person

) AS week1, 
(

SELECT SUM( item1 + item2 + item3 ) AS w2sum
FROM table 
WHERE week = 1 AND week = 2
AND iteration
IN (

SELECT MAX( iteration ) 
FROM table
)
    GROUP BY person

) AS week2

GROUP BY person

---

我认为您可以使用条件聚合来做您想做的事情：

select person,
       sum(case when week in (1) then item1 + item2 + item3 else 0 end) as week1,
       sum(case when week in (1, 2) then item1 + item2 + item3 else 0 end) as week2
       sum(case when week in (1, 2, 3) then item1 + item2 + item3 else 0 end) as week3
from table t
where not exists (select 1
                  from table t2
                  where t2.person = t.person and
                        t2.week = t.week and
                        t2.iteration > t.iteration
                 )
group by person;

where

子句获取每个人每周的最后一次迭代