Mysql多重计数和选择

嗨，伙计们，我正在为特定的ID计算特定的项目

数据库结果

name                      remarks
joseph greggory           On time
joseph greggory           On time
lara joy                  On time
lara joy                  Absent
Mark Joben                On time
Mark Joben                Absent
Isnaira Lyn               Absent
Isnaira Lyn               Absent

结果应该是

name                  On time         Late       Absent
joseph Greggory         2              0            0
Lara Joy                1              0            1
Mark Joben              1              0            1
Isnaira Lyn             0              0            2

提前谢谢你们

SELECT  name,
        SUM(CASE WHEN remarks = 'On time' THEN 1 ELSE 0 END) `On time`,
        SUM(CASE WHEN remarks = 'Late' THEN 1 ELSE 0 END) `Late`,
        SUM(CASE WHEN remarks = 'Absent' THEN 1 ELSE 0 END) `Absent`  
FROM    TableName
GROUP   BY name

你可以试试这个

select name,
       count(case when remarks = 'On time' then 1 end) "On time",
       count(case when remarks = 'Late' then 1 end) "Remarks",
       count(case when remarks = 'Absent' then 1 end) "Absent"
from table1
group by name;

您可以尝试以下方法：

SELECT  name,
        COUNT(IF(remarks = 'On time', 1, NULL)) `On time`,
        COUNT(IF(remarks = 'Late', 1, NULL)) `Late`,
        COUNT(IF(remarks = 'Absent', 1, NULL)) `Absent`  
FROM    tbl
GROUP   BY name

---

这里没有提供足够的信息来回答这个问题。什么疑问？桌子的结构是什么？如果您可以编辑您的问题，为清晰起见，请将其标记为版主审阅。