Mysql SQL-如何联接3个表并选择多个列的计数

我被困在这种情况下，不知道如何编写select查询以得到我想要的结果。情况是这样的

我有3个表会话、请求、日志

会话表

# session table to store sessions data
ID     user
------------
1      John
2      Sarah

# request table to store `http` requests come to me
ID     session
------------
1      1
2      1
3      1
4      1
5      2
6      NULL

# log table to store the logs that I record in my php code and store_
# them in the database while processing the requests 
ID     request
------------
1      1
2      1
3      2

请求表

# session table to store sessions data
ID     user
------------
1      John
2      Sarah

# request table to store `http` requests come to me
ID     session
------------
1      1
2      1
3      1
4      1
5      2
6      NULL

# log table to store the logs that I record in my php code and store_
# them in the database while processing the requests 
ID     request
------------
1      1
2      1
3      2

日志表

# session table to store sessions data
ID     user
------------
1      John
2      Sarah

# request table to store `http` requests come to me
ID     session
------------
1      1
2      1
3      1
4      1
5      2
6      NULL

# log table to store the logs that I record in my php code and store_
# them in the database while processing the requests 
ID     request
------------
1      1
2      1
3      2

---

我想要的是选择每个会话以及在此会话中发出的请求数，以及日志数。我希望结果是

#sessions result
+----+-------+----------+------+
| ID | USER  | requests | logs |
+----+-------+----------+------+
| 1  | John  |    4     |  3   |
+----+-------+----------+------+
| 2  | Sarah |    1     | NULL |
+----+-------+----------+------+

---

我所做的是使用连接和按会话分组

select session.*,count(request.id) as requests,count(log.id) as logs
from session left join request on session.id=request.session
left join log on request.id=log.request group by session.id

问题是，当我这样做时，如果一个请求有超过1个日志，那么在我们的情况下，它将被类似于join的请求1复制，该请求有日志1和日志2

# wrong result !! not what I want. notice the count of requests in session 1
+----+-------+----------+------+
| ID | USER  | requests | logs |
+----+-------+----------+------+
| 1  | John  |  ((5))   |  3   |
+----+-------+----------+------+
| 2  | Sarah |    1     | NULL |
+----+-------+----------+------+

我做错了什么

---

谢谢

请抓住我的方法。我还没有编译这个查询。 我需要强调这一点

(select count(*) from log where request.id=log.request)

完整SQL

select session.id,session.user,count(request.id) as requests,logs from (
 select session.*,(select count(*) from log where request.id=log.request) as     
logs from sesson join
request on sesson.id=request.sesson group by request.id
)group by session.id

---

试着抓住我的方法。我还没有编译这个查询。 我需要强调这一点

(select count(*) from log where request.id=log.request)

完整SQL

select session.id,session.user,count(request.id) as requests,logs from (
 select session.*,(select count(*) from log where request.id=log.request) as     
logs from sesson join
request on sesson.id=request.sesson group by request.id
)group by session.id

---

我能说什么？我能说什么呢？谢谢你，先生，我会尝试你的方法谢谢你，先生，我会尝试你的方法