MySQL需要一个使用GROUPBY column_a的查询来忽略列_b的重复项

我正试图得到一份关于用户获奖数量的报告。即，玩家如何获得全部3项大奖，有多少人获得2项大奖，等等

+--------+--------+
| player | prize  |
+--------+--------+
|   1    |   1    |
+--------+--------+
|   1    |   1    |
+--------+--------+
|   1    |   2    |
+--------+--------+
|   1    |   3    |
+--------+--------+
|   2    |   1    |
+--------+--------+
|   2    |   2    |
+--------+--------+

我需要的报告应该是这样的：

+-----------+------------+
| prize_qty | player_qty |
+-----------+------------+
|      3    |      1     |
+-----------+------------+
|      2    |      1     |
+-----------+------------+

以下代码已关闭：

SELECT DISTINCT COUNT(*) as player_qty, prize_qty FROM 
(SELECT count( * ) AS prize_qty FROM `prizes` GROUP BY player)
as t1 GROUP BY player_qty

但它返回的是：

+-----------+------------+
| prize_qty | player_qty |
+-----------+------------+
|      4    |      1     |
+-----------+------------+
|      2    |      1     |
+-----------+------------+

我需要它来忽略玩家1曾两次赢得大奖1，但我不确定如何进一步消除重复。

你说的

SELECT DISTINCT COUNT(*) as player_qty, prize_qty FROM 
(SELECT count( * ) AS prize_qty FROM `prizes` GROUP BY player, prize)
as t1 GROUP BY player_qty

玩家如何获得全部3项奖品，有多少人获得2项奖品，等等

+--------+--------+
| player | prize  |
+--------+--------+
|   1    |   1    |
+--------+--------+
|   1    |   1    |
+--------+--------+
|   1    |   2    |
+--------+--------+
|   1    |   3    |
+--------+--------+
|   2    |   1    |
+--------+--------+
|   2    |   2    |
+--------+--------+

及

我需要它来忽略玩家1两次赢得奖品1

那么，当一个玩家多次获得同一奖项的事实被消除后，你不应该计算每个奖项的玩家数吗

SELECT COUNT(*) AS player_qty, prize AS prize_qty
FROM
  (SELECT DISTINCT prize, player FROM prizes) AS T1
GROUP BY prize 

试试这个：

SELECT DISTINCT COUNT(player) as player_qty, prize_qty FROM 
(SELECT count( distinct prize ) AS prize_qty, player FROM `prizes` GROUP BY player)
as t1 GROUP BY prize_qty

---

你就在那里。最终的结果是，选择不同的计数*作为玩家数量，选择计数中的奖品数量*作为选择不同的奖品中的奖品数量，奖品中的玩家作为t2组按玩家作为t1组按奖品数量