Mysql 我想结合两个sql查询

我想结合两个查询结果和两个查询的最终结果显示

我试着和工会合作，但没有成功

Select Distinct PersonNameWorked, COUNT(ProcessInstanceAppianId)as Num_Of_Jobs,  sum(ExpectedTaskEffort) as Workunits,
cast((cast((sum(TaskInstanceEffort) / 60.00) as Decimal(5,2)))/count (Distinct  cast(TaskInstanceCompleted as date) ) as Decimal(5,2)) as WorkingHours,
ROUND((1.00- sum(CAST(TaskInstanceEffort AS FLOAT))/sum(CAST(ExpectedTaskEffort AS FLOAT)))*100,2) as EfforVariance
from pathfinder..PFTask

where TaskInstanceCompleted  between '2019-9-03 00:30:00' and '2019-9-04 00:30:00'
  and KeyProcessStream in (26769,26768,28788,26760,26761,26755,29529)
and KeyPerson in (1347718,1332622,619682)
--and ProcessInstanceAppianId='-2136985491'
--and TaskInstanceCompleted
group by PersonNameWorked, KEYPERSON
order by PersonNameWorked asc
union all
select PersonNameWorked, cast(sum(PFTaskInstanceRating)*1.00/count(distinct ProcessInstanceAppianId) as decimal (5,2))as Rating
from pathfinder..PFTask
where TaskInstanceCompleted  between '2019-9-03 00:30:00' and '2019-9-04 00:30:00'
and KeyPerson in (1347718,1332622,619682)
and PFTaskInstanceRating is not null
group by PersonNameWorked, KEYPERSON
order by PersonNameWorked asc 

味精156，第15级，状态1，第17行

---

关键字“union”附近的语法不正确。

对于

union all/union

，您需要在两个查询中具有相同的列数，这两个查询在您的情况下都会丢失，因此会引发错误

Select Distinct PersonNameWorked, COUNT(ProcessInstanceAppianId)as Num_Of_Jobs,  sum(ExpectedTaskEffort) as Workunits,
cast((cast((sum(TaskInstanceEffort) / 60.00) as Decimal(5,2)))/count (Distinct  cast(TaskInstanceCompleted as date) ) as Decimal(5,2)) as WorkingHours,
ROUND((1.00- sum(CAST(TaskInstanceEffort AS FLOAT))/sum(CAST(ExpectedTaskEffort AS FLOAT)))*100,2) as EfforVariance
from pathfinder..PFTask
where TaskInstanceCompleted  between '2019-9-03 00:30:00' and '2019-9-04 00:30:00'
  and KeyProcessStream in (26769,26768,28788,26760,26761,26755,29529)
and KeyPerson in (1347718,1332622,619682)
--and ProcessInstanceAppianId='-2136985491'
--and TaskInstanceCompleted
group by PersonNameWorked, KEYPERSON

union all

select PersonNameWorked, null,null,null,cast(sum(PFTaskInstanceRating)*1.00/count(distinct ProcessInstanceAppianId) as decimal (5,2))as Rating
from pathfinder..PFTask
where TaskInstanceCompleted  between '2019-9-03 00:30:00' and '2019-9-04 00:30:00'
and KeyPerson in (1347718,1332622,619682)
and PFTaskInstanceRating is not null
group by PersonNameWorked, KEYPERSON

---

作为对fa06s答案的补充，由于他提出了一个非常好的观点，即两个查询之间的列计数必须相等，因此此错误是由于您尝试按每个查询排序，然后执行并集：

SELECT a FROM table1
UNION 
SELECT b FROM table2
UNION 
SELECT c FROM table3
ORDER BY a            <--the column is named after whatever the first query called it

在合并之前，不能按每个查询排序。在所有工会结束后，你一次完成命令

对:

SELECT.. 
FROM ... 
UNION 
SELECT ... 
FROM ... 
ORDER BY ... <-- just order by once. It works on the whole union output

删除ORDER BY后，您将面临有关列计数的错误：

联合的查询必须具有相同的列数，因为结果集垂直地粘在一起：查询1上的5列必须与查询2上的5列匹配，以便查询1中的50行和查询2中的100行可以成为一个150行长的结果集

如果查询2中的某些列没有任何值，请将其设为null：

  SELECT 1 as a, 2 as b
  UNION 
  SELECT 2, null         <-- there are no values for column b for this query,
                             so just use a constant value like 0, 1, null..
                             whatever is appropriate
  ORDER BY a

选择1作为a，选择2作为b
联合
SELECT 2，null通常按与所选列相同的列进行分组，但作为设置函数参数的列除外。查询中只能有一个order BY子句包含union all。删除第一个order by子句。您几乎不需要将GROUP by与SELECT DISTINCT组合在一起。SQL Server的标记为
SQL Server
，并且还存在版本标记。请在以后的所有问题中使用
sql server
标记加上版本标记，如
sql-server-2017
mysql
tag是针对oracle corporation的一款具有不同语法的竞争产品的，上面的查询有效，但结果与预期不符，所以基本上我的问题是，我想要两个查询的结果，但最终结果包含，PersonNameWorked，工作数量，工作单位，工作时间，EfforVariance and Rating@FA06您已经删除了
ORDER BY
您可能想提及的是，错误消息是由于尝试在union之前订购而引起的，而不是因为列数不同。那将是另一个错误message@RiggsFolly，联合订货有时并不像我们所做的那样有效think@fa06我知道，我只是在UVing之后建议你告诉OP你为什么要删除它：）@fa06忠实地承诺它会；看看我刚才添加到答案中的屏幕截图。当然，OP标记为
mysql
并使用
sqlserver
，这并没有帮助，mysql可能会接受各种类似的****ty行为。。但是OP肯定在使用sqls；这不是mysql错误消息
SELECT * FROM
(
  SELECT a 
  UNION 
  SELECT b 
  UNION 
  SELECT c  
) x
ORDER BY x.a

  SELECT 1 as a, 2 as b
  UNION 
  SELECT 2, null         <-- there are no values for column b for this query,
                             so just use a constant value like 0, 1, null..
                             whatever is appropriate
  ORDER BY a