MySql在同一查询中对多个时间戳查询进行分组

我正在尝试编写一个MySQL函数，该函数将使我能够在设定的时间段（即1天、1周、1个月等）内汇总工作人员完成的工作量。完成的每项工作在数据库中生成1个ID条目

条目的日期设置为时间戳

我的问题是，我不清楚我将如何对数据库进行多次调用，以检查在设置的时间戳期间有多少条记录

下面是数据库表

CREATE TABLE staffwork(
staff_id MEDIUMINT UNSIGNED NOT NULL, 


id_of_work_inserted MEDIUMINT UNSIGNED NOT NULL,
job_id MEDIUMINT UNSIGNED NOT NULL,

data_table VARCHAR (65) NOT NULL, 
entrytime int(11) NOT NULL, 

INDEX message (staff_id) 


); 

下面是将数据放入表中的查询，即时间戳：

INSERT INTO staffwork
 (staff_id, job_id, id_of_work_inserted, data_table,  entrytime )
VALUES ('$staff_id', '$job_id', '$id_of_job', '$data_table', UNIX_TIMESTAMP(now()) )";      

SELECT 
            COUNT(job_id) AS totalWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id

SELECT 
            COUNT(job_id) AS oneDaysWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 day    

SELECT 
            COUNT(job_id) AS oneWeekWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 week

SELECT 
            COUNT(job_id) AS oneMonthWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 month

下面是我的SQL函数：

CREATE TABLE staffwork(
staff_id MEDIUMINT UNSIGNED NOT NULL, 


id_of_work_inserted MEDIUMINT UNSIGNED NOT NULL,
job_id MEDIUMINT UNSIGNED NOT NULL,

data_table VARCHAR (65) NOT NULL, 
entrytime int(11) NOT NULL, 

INDEX message (staff_id) 


); 

功能statsForEmployeesWork（$staff\U id） { 全球$dbc

$select = " SELECT 
                COUNT(job_id) AS totalWorkDone,
                COUNT(job_id) AS oneDaysWorkDone,
                COUNT(job_id) AS oneWeekWorkDone,
                COUNT(job_id) AS oneMonthWorkDone
                ";

$from   = " FROM 
            staffwork 
                ";

$where = " WHERE
                 staff_id = '$staff_id
               AND  
                  entrytime  >= now() - interval '1 day'     
               AND 
                  entrytime  >= now() - interval '1 week'
               AND
                  entrytime  >= now() - interval '1 month '";    

$query  = $select.$from. $where;

$result = mysqli_query ($dbc, $query)

    return $result ; 
} 

---

我非常感谢您在这方面提供的帮助和建议。

您的entrytime字段是一个int，这意味着您不能使用直接的mysql日期数学，您最终将执行以下操作

12345678 > '2013-11-14'

这是没有意义的。请将日期范围转换为整数，或将整数字段转换为正常日期：

WHERE FROM_UNIXTIME(entrytime) >= now() - interval 1 day
WHERE entrytime >= UNIX_TIMESTAMP(now() - interval 1 day)

更好的方法是，将entrytime转换为实际的datetime字段，然后原始查询将按预期工作。

在本子句中

              entrytime  >= now() - interval '1 day'     
           AND 
              entrytime  >= now() - interval '1 week'
           AND
              entrytime  >= now() - interval '1 month

第一个表达式将丢弃所有大于1天的条目

            COUNT(job_id) AS totalWorkDone,
            COUNT(job_id) AS oneDaysWorkDone,
            COUNT(job_id) AS oneWeekWorkDone,
            COUNT(job_id) AS oneMonthWorkDone

都是一样的

您应该拆分查询以分别计算每个期间：

totalWorkDone:

INSERT INTO staffwork
 (staff_id, job_id, id_of_work_inserted, data_table,  entrytime )
VALUES ('$staff_id', '$job_id', '$id_of_job', '$data_table', UNIX_TIMESTAMP(now()) )";      

SELECT 
            COUNT(job_id) AS totalWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id

SELECT 
            COUNT(job_id) AS oneDaysWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 day    

SELECT 
            COUNT(job_id) AS oneWeekWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 week

SELECT 
            COUNT(job_id) AS oneMonthWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 month

oneDaysWorkDone:

INSERT INTO staffwork
 (staff_id, job_id, id_of_work_inserted, data_table,  entrytime )
VALUES ('$staff_id', '$job_id', '$id_of_job', '$data_table', UNIX_TIMESTAMP(now()) )";      

SELECT 
            COUNT(job_id) AS totalWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id

SELECT 
            COUNT(job_id) AS oneDaysWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 day    

SELECT 
            COUNT(job_id) AS oneWeekWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 week

SELECT 
            COUNT(job_id) AS oneMonthWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 month

oneWeekWorkDone:

INSERT INTO staffwork
 (staff_id, job_id, id_of_work_inserted, data_table,  entrytime )
VALUES ('$staff_id', '$job_id', '$id_of_job', '$data_table', UNIX_TIMESTAMP(now()) )";      

SELECT 
            COUNT(job_id) AS totalWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id

SELECT 
            COUNT(job_id) AS oneDaysWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 day    

SELECT 
            COUNT(job_id) AS oneWeekWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 week

SELECT 
            COUNT(job_id) AS oneMonthWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 month

oneMonthWorkDone:

INSERT INTO staffwork
 (staff_id, job_id, id_of_work_inserted, data_table,  entrytime )
VALUES ('$staff_id', '$job_id', '$id_of_job', '$data_table', UNIX_TIMESTAMP(now()) )";      

SELECT 
            COUNT(job_id) AS totalWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id

SELECT 
            COUNT(job_id) AS oneDaysWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 day    

SELECT 
            COUNT(job_id) AS oneWeekWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 week

SELECT 
            COUNT(job_id) AS oneMonthWorkDone

       FROM 
        staffwork 

       WHERE
             staff_id = $staff_id
           AND  
              entrytime  >= now() - interval 1 month

---

当然，将

entrytime

转换为

datetime

字段

你好，克劳斯特罗福，谢谢你的回复。我不清楚。然后我是否要执行3个单独的SQL函数来获取数据。2.你是指如何将entrytime转换为datetime字段的。我该怎么做你好，非常感谢你的回复。我有点困惑为什么你在查询中做了两个WHERE cluase。请你解释一下。谢谢你的帮助。只举两种方法的例子。假装它们是“这边或这边”