在MySQL中查找具有重复记录的ID

我想提取MySQL数据库中的重复记录

----------------------------
| id | column_a | column_b |
|----|----------|----------| 
| 1  |    a     |    b     |
| 2  |    a     |    c     |
| 3  |    a     |    d     |
| 4  |    a     |    b     |
| 5  |    b     |    e     |
| 6  |    c     |    a     |
| 7  |    c     |    d     |
| 8  |    e     |    a     |
| 9  |    e     |    a     |
----------------------------

我想把它拉出来，这样它就能显示出每一行都是重复的。比如：

------
| id |
|----|
| 1  |
| 4  |
| 8  |
| 9  |
------

或

关于如何做到这一点，您有什么想法吗？

试试

group\u contact（）

函数

select group_concat(id) as duplicate_ids,
       columna, 
       columnb
from your_table
group by columna, columnb
having count(id) > 1

select group_concat(id) duplicate_ids ,column_a, column_b
from <table>
group by column_a, column_b

选择组（id）重复id、列a、列b
从
按列a、列b分组

试试

GROUP\u CONCAT

SELECT    GROUP_CONCAT(id), column_A, column_B
FROM      mytable
GROUP BY  columnA, columnB
HAVING    COUNT(id) > 1

SELECT    GROUP_CONCAT(id), column_A, column_B
FROM      mytable
GROUP BY  columnA, columnB
HAVING    COUNT(id) > 1

SELECT
    GROUP_CONCAT(id) as ids,
    column_a,
    column_b 
FROM table
GROUP BY column_a, column_b 
HAVING COUNT(id) > 1