Mysql ORDER BY和GROUP BY的正确顺序是什么

我是mysql的初学者 有人能帮我解决第5行的错误吗：

select a.*, count(b.user_id) as attempts from survey a 
left join survey_attempt b on a.survey_id = b.attempt_surveyid 
where a.survey_status != 0 
order by survey_order asc 
GROUP by a.survey_id

---

在

orderby

子句之前使用

groupby

子句

详情如下:

select a.*, count(b.user_id) as attempts from survey a 
left join survey_attempt b on a.survey_id = b.attempt_surveyid 
where a.survey_status != 0 
GROUP by a.survey_id
order by survey_order asc 

---

您的ORDER BY应该在GROUP BY之后。

您不允许在您的GROUP BY之前下单，因此您的查询应该如下所示：

select a.*, count(b.user_id) as attempts 
from survey a 
   left join survey_attempt b on a.survey_id = b.attempt_surveyid 
where a.survey_status != 0 
group by a.survey_id
order by survey_order asc 

可以找到更多细节，其中提出了一个类似的问题，并得到了更详细的回答

---

作为旁注，请尽量避免使用

*

，并改为使用必填列

切换“分组依据”和“排序依据”在这一行中指定表名

order by a.survey\u order asc

。您想做什么？我试图创建“分组依据”和“排序依据”，我从下面的帮助中得到了答案，谢谢大家