Mysql 为1个值匹配2行的SQL查询

如何编写查询，以查找一列中的2个特定值与另一列中的每1个值的匹配情况？我使用的是MySQL数据库

例如：

| test_id | animal_type | classification_id |
----------------------------------------------
    1          cat             456
    2          dog             456
    3          mongoose        456
    4          cat             123

我想写一个查询，查找表中出现的同一动物类型的分类id为“123”和“456”的两行

如果我写了以下内容，它就不起作用了，因为我不知道如何在这个查询中包含animal_type

SELECT *
FROM test_table
WHERE classification_id = '123' AND classification_id = '456' 

如何编写查询以选择所有同时具有123和456作为特定动物类型分类id的行？

您可以使用：

SELECT animal_type
FROM test_table
WHERE classification_id IN (123, 456)
GROUP BY animal_type
HAVING COUNT(DISTINCT classification_id) = 2;

如果您需要整行：

SELECT *
FROM test_table
WHERE animal_type IN (SELECT animal_type
                      FROM test_table
                      WHERE classification_id IN (123, 456)
                      GROUP BY animal_type
                      HAVING COUNT(DISTINCT classification_id) = 2)

使用group by和have

SELECT count(test_id) as animal_count,test_table.*
FROM test_table
WHERE classification_id = '123' AND classification_id = '456' 
GROUP BY animal_type HAVING animal_count > 2