Mysql 将满足其他几个列条件的列组合在一起
我需要能够对一列(小时)求和,其中它匹配其他列中的几个条件。这就是桌子的样子Mysql 将满足其他几个列条件的列组合在一起,mysql,select,duplicates,inner-join,group-concat,Mysql,Select,Duplicates,Inner Join,Group Concat,我需要能够对一列(小时)求和,其中它匹配其他列中的几个条件。这就是桌子的样子 payrollid, agentid, ptid, serviceid, dateincurred ,hours 209 , 284 , 580 , 1320 , '2014-05-19' ,4 209 , 284 , 569 , 1433 , '2014-45-19' ,2 209 , 284 , 580 , 1433 , '2014-05-19
payrollid, agentid, ptid, serviceid, dateincurred ,hours
209 , 284 , 580 , 1320 , '2014-05-19' ,4
209 , 284 , 569 , 1433 , '2014-45-19' ,2
209 , 284 , 580 , 1433 , '2014-05-19' ,2
209 , 284 , 569 , 1433 , '2014-05-19' ,2
209 , 284 , 580 , 1320 , '2014-05-19' ,7
209 , 284 , 580 , 19 , '2014-05-20' ,1
209 , 284 , 569 , 1318 , '2014-45-21' ,2
209 , 284 , 580 , 1320 , '2014-45-22' ,1
209 , 284 , 580 , 16 , '2014-05-23' ,1
209 , 284 , 569 , 1445 , '2014-45-24' ,9
209 , 284 , 580 , 1427 , '2014-05-25' ,1
209 , 284 , 569 , 1326 , '2014-05-28' ,1
209 , 284 , 569 , 1445 , '2014-45-29' ,4
209 , 284 , 569 , 1320 , '2014-05-29' ,1
209 , 284 , 569 , 1347 , '2014-45-29' ,5
209 , 284 , 580 , 1320 , '2014-05-30' ,1
209 , 284 , 569 , 1347 , '2014-05-30' ,5
209 , 284 , 580 , 1326 , '2014-05-31' ,1
209 , 284 , 580 , 1348 , '2014-06-01' ,1
209 , 284 , 580 , 24 , '2014-06-01' ,1
查询结果如下:
SELECT
p.agentid,
p.ptid,
p.dateincurred,
p.serviceid,
(
SELECT
GROUP_CONCAT(p.hours)
FROM payroll_detail_temp p3
WHERE p3.payrollid = '209'
AND (
p3.dateincurred BETWEEN '2014-05-19'
AND DATE_ADD('2014-05-19', INTERVAL 6 DAY))
AND p3.serviceid = p.serviceid
GROUP BY
p3.serviceid
LIMIT 1
) AS week1,
(
SELECT
GROUP_CONCAT(p2.hours)
FROM
payroll_detail_temp p2
WHERE
p2.payrollid = '209'
AND (
p2.dateincurred BETWEEN '2014-05-25'
AND DATE_ADD('2014-05-25', INTERVAL 6 DAY))
AND p2.serviceid = p.serviceid
GROUP BY
p2.serviceid,
p2.dateincurred
LIMIT 1
) AS week2,
GROUP_CONCAT(p.serviceid) AS services,
GROUP_CONCAT(p.dateincurred) AS dates
FROM
payroll_detail_temp p
INNER JOIN agent ON (p.agentid = agent.id)
INNER JOIN service ON (p.serviceid = service.id)
INNER JOIN payer ON (p.payerid = payer.id)
INNER JOIN prov ON (p.provid = prov.id)
INNER JOIN patient ON (p.ptid = patient.id)
WHERE
p.payrollid = '209'
AND (
p.dateincurred BETWEEN '2014-05-19'
AND DATE_ADD('2014-05-25', INTERVAL 14 DAY)
)
GROUP BY
p.serviceid,
p.dateincurred
Week1和Week2列将表示两周内的工作小时数,在本例中,它设置为2014-05-19和2014-06-01。因此,Week1列将对agentid、ptid、serviceid匹配的时间进行分组,发生的日期范围为2014-05-19至2014-05-25。第2周也是如此,发生日期在2014年5月26日至2014年6月01日之间
我的查询的问题是我得到了重复的结果,就像下面查询结果中显示的最后两个结果一样。Week1应该有9.00,Week2需要为空;同样,在下面的行中,Week1应为null,Week2应为4.00。第5排和第6排也是如此。在第5行,第1周应仅为7.00、4.00和1.00,第2周应为空。第6行不应该存在
我知道存在重复项,因为DateEncurrented字段与查询重叠,但我无法找到其他字段。如果您有如第一张图片所示的表。然后,您可以通过此查询轻松实现所需:
SELECT
PAYROLLID,
AGENTID,
PTID,
SERVICEID,
DATEINCURED,
CASE WHEN (DATEINCURRED BETWEEN '2014-05-19' AND '2014-05-25') THEN SUM(HOURS) END WEEK1,
CASE WHEN (DATEINCURRED BETWEEN '2014-05-26' AND '2014-06-01') THEN SUM(HOURS) END WEEK2
FROM
YOUR_TABLE_NAME
GROUP BY
PAYROLLID,
AGENTID;
我不得不按几个字段分组,以获得我想要的数据,但这在其他方面是有效的!非常感谢你。