查询mysql返回错误的和

朋友们，下午好

我正在开发一个应用程序，我有一个页面显示“房间”顶部。我想得到某个“房间”内所有用户的应用程序点数之和

我已经完成了以下查询：

SELECT rooms.id, rooms.name, SUM(users.points)
FROM users, room_players, rooms
WHERE users.id = room_players.user AND room_players.room = rooms.id

这将返回所有房间内所有用户的积分之和，我希望每个房间内所有用户的应用程序积分之和

有人能帮我找到这个查询中的错误吗

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现在非常感谢。

可能需要GROUPBY子句

SELECT rooms.id, rooms.name, SUM(users.points) 
FROM users, room_players, rooms 
WHERE users.id = room_players.user AND room_players.room = rooms.id
GROUP BY  rooms.id, rooms.name

使用更现代的联接：-

SELECT rooms.id, rooms.name, SUM(users.points) 
FROM users
INNER JOIN room_players ON users.id = room_players.user
INNER JOIN rooms ON room_players.room = rooms.id
GROUP BY  rooms.id, rooms.name

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使用GROUP BY room.id按房间对总和进行分组

您应该使用联接和GROUP BY look：

Select 
   c.id,c.name,sum(a.points) from users a
Inner join room_players b
   On (a.id=b.user)
Inner join rooms c
   On (b.room=c.id)
Group by c.id,c.name

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这个问题似乎离题了，因为它缺乏基本的研究。非常感谢你的帮助！致以最良好的祝愿。非常感谢您的帮助！致以最良好的祝愿。非常感谢您的帮助！顺致敬意，