按列组合mysql查询

是否存在按列组合mysql查询的方法？我有以下疑问

select  count(ticket_id) as numInProgress from ost_ticket where status
 = 'in progress' and topic_id not in (select topic_id from ost_org_site_map)

 select  count(ticket_id) as numAssigned from ost_ticket where status =
 'open' and topic_id not in (select topic_id from ost_org_site_map)

我正试图得到以下格式的结果

---numInProgress | numAssigned---
            2    |     8
---------------------------------

---

只需将它们用作select语句中的子查询，例如

SELECT ($statement1$),($statement2$)

或与您的查询：

SELECT (select count(ticket_id) as numInProgress from ost_ticket where status = 'in progress' and topic_id not in (select topic_id from ost_org_site_map)) as numInProgress ,(select count(ticket_id) as numAssigned from ost_ticket where status = 'open' and topic_id not in (select topic_id from ost_org_site_map)) as numAssigned;

你可以试试这个：

SELECT (select count(ticket_id) as numInProgress 
        from ost_ticket where status = 'in progress' 
        and topic_id not in (select topic_id from ost_org_site_map)),
       (select count(ticket_id) as numAssigned 
        from ost_ticket where status = 'open' 
        and topic_id not in (select topic_id from ost_org_site_map));

ie将两个查询合并在select语句中生成一个子查询。

可能是这样的：

SELECT sum(CASE OT.status when 'in progress' ,1,0) as numInProgress,
       sum(CASE OT.status when 'open' ,1,0) as numAssigned 
FROM ost_ticket OT
LEFT JOIN OST_ORG_SITE_MAP OSM
 ON OT.topic_Id =OSM.Topic_ID
WHERE OT.status in ('in progress', 'open')
  and OSM.Topic_ID is null

左边的连接允许我们在主题Id上连接OST_票证和OST_组织站点地图。当站点地图表中没有主题Id时，我们有一个等价于主题Id不在

我们将状态合并为只查找进行中和打开的状态，并使用状态的案例语句来确定需要计算的内容。由于count将返回1和0的值，因此我们需要使用sum将1和0相加