Neo4j：查找具有包含字符串的属性名称的节点（在属性名称中，而不是在属性值中）

是否有方法查找具有特定字符串的属性的所有节点？
例如，这里有“ID”：

（这不起作用）

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谢谢

这只会给你钥匙

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") RETURN n, KEYS(n) AS myKeys

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这将只提供值

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
RETURN n, [x IN KEYS(n) WHERE x =~".*ID" | n[x]] AS myValues

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
WITH n, [x IN KEYS(n) WHERE x =~".*ID" | x] AS myKeys
RETURN id(n) AS nodeId, apoc.map.submap(n, myKeys) as submap

如果您有apoc，这将为您提供键和值

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
RETURN n, [x IN KEYS(n) WHERE x =~".*ID" | n[x]] AS myValues

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
WITH n, [x IN KEYS(n) WHERE x =~".*ID" | x] AS myKeys
RETURN id(n) AS nodeId, apoc.map.submap(n, myKeys) as submap

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这只会给你钥匙

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") RETURN n, KEYS(n) AS myKeys

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这将只提供值

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
RETURN n, [x IN KEYS(n) WHERE x =~".*ID" | n[x]] AS myValues

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
WITH n, [x IN KEYS(n) WHERE x =~".*ID" | x] AS myKeys
RETURN id(n) AS nodeId, apoc.map.submap(n, myKeys) as submap

如果您有apoc，这将为您提供键和值

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
RETURN n, [x IN KEYS(n) WHERE x =~".*ID" | n[x]] AS myValues

MATCH (n) WHERE ANY(x IN KEYS(n) WHERE x =~".*ID") 
WITH n, [x IN KEYS(n) WHERE x =~".*ID" | x] AS myKeys
RETURN id(n) AS nodeId, apoc.map.submap(n, myKeys) as submap

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极好的！非常感谢。我返回n{.*}。你知道有没有办法只返回x属性的值？看起来n.x不承认x是属性。我很高兴它有帮助！我编辑了我的答案，给你一些不同的选择。太棒了！非常感谢。我返回n{.*}。你知道有没有办法只返回x属性的值？看起来n.x不承认x是属性。我很高兴它有帮助！我编辑了我的答案，给你一些不同的选择。