Neo4j如何从某个起始节点递归删除节点

在我的Neo4j数据库中，我有以下实体：

@NodeEntity
public class Product {

    private final static String CONTAINS = "CONTAINS";
    private final static String DEFINED_BY = "DEFINED_BY";
    private final static String VOTED_FOR = "VOTED_FOR";
    private final static String PARENT = "PARENT";
    private final static String CREATED_BY = "CREATED_BY";

    @GraphId
    private Long id;

    @RelatedTo(type = PARENT, direction = Direction.INCOMING)
    private Product parent;

    @RelatedTo(type = CONTAINS, direction = Direction.OUTGOING)
    private Set<Product> childProducts = new HashSet<>();

    @RelatedTo(type = DEFINED_BY, direction = Direction.INCOMING)
    private Set<Criterion> criterias = new HashSet<>();

    @RelatedTo(type = VOTED_FOR, direction = Direction.INCOMING)
    private Set<Vote> votes = new HashSet<>();

    @RelatedTo(type = CREATED_BY, direction = Direction.OUTGOING)
    private User user;

}    

@NodeEntity
public class Criterion {

    private final static String CREATED_BY = "CREATED_BY";
    private final static String DEFINED_BY = "DEFINED_BY";

    @GraphId
    private Long id;

    @RelatedTo(type = DEFINED_BY, direction = Direction.OUTGOING)
    private Product owner;

    @RelatedTo(type = CREATED_BY, direction = Direction.OUTGOING)
    private User user;

}

@NodeEntity
public class Vote {

    private static final String VOTED_ON = "VOTED_ON";
    private final static String VOTED_FOR = "VOTED_FOR";
    private static final String CREATED_BY = "CREATED_BY";

    @GraphId
    private Long id;

    @RelatedTo(type = VOTED_FOR, direction = Direction.OUTGOING)
    private Product product;

    @RelatedTo(type = VOTED_ON, direction = Direction.OUTGOING)
    private Criterion criterion;

    @RelatedTo(type = CREATED_BY, direction = Direction.OUTGOING)
    private User user;

}

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但它只删除产品，不删除开始节点上的投票以及所有子标准和投票。请帮我一个正确的密码查询。谢谢。

我把它分成两个问题。第一个递归地向下收集产品层次结构，第二个递归地删除一个产品节点及其直接环境

获取产品层次结构很简单：

MATCH (p:Product)-[:CONTAINS*]->(childProduct)
WHERE id(p) = {productId}
RETURN id(childProduct) as id

要删除一个产品，我们需要删除该产品节点的所有关系。此外，如果所有相关节点既不是用户（您想保留它们）也不是产品（想想父产品，它们也应该保留），那么也需要删除它们。我们还需要确保目标节点未连接，这就是为什么第二个可选匹配：

MATCH (p:Product) 
OPTIONAL MATCH (p)-[r]-(t)
WHERE id(p) = {productId}
DELETE r,p
WITH t
OPTIONAL MATCH (t)-[r2:VOTE_ON|:CREATED_BY]->()
WHERE none(x in labels(t) WHERE x in ["User", "Product"])
DELETE t,r2

我没有亲自测试这个查询，因为您没有提供测试图。因此，把这当作一个想法，并修改它，直到它的工作

更新 在一次聊天中，我们发现此cypher语句解决了问题，请注意，

产品

已被模型中的

决策

标签所取代：

MATCH (p:Decision) 
WHERE p.name = "NoSQL" 
WITH p 
OPTIONAL MATCH (p)-[r]-(t) 
DELETE p,r 
WITH t,r 
OPTIONAL MATCH (t)-[r2:VOTED_ON|:CREATED_BY|:VOTED_FOR]-() 
WITH t, r2,r 
WHERE none(x in labels(t) WHERE x in ["User", "Decision"]) 
DELETE t,r2

---

谢谢你的回答！所以，我需要收集所有子产品ID，然后对每个ID调用第二个查询？秩序重要吗？没错。如果在{myIdList}中使用

whereid（p），也可以将多个id作为数组参数传入第二条语句。在尝试之前，请记住备份您的数据。顺序无关紧要。谢谢！看起来查询的这部分不起作用-WHERE none（标签中的x（t）WHERE x在['User'，'Product']），因为它还删除用户和其他产品..您能提供一个示例图吗？
MATCH (p:Decision) 
WHERE p.name = "NoSQL" 
WITH p 
OPTIONAL MATCH (p)-[r]-(t) 
DELETE p,r 
WITH t,r 
OPTIONAL MATCH (t)-[r2:VOTED_ON|:CREATED_BY|:VOTED_FOR]-() 
WITH t, r2,r 
WHERE none(x in labels(t) WHERE x in ["User", "Decision"]) 
DELETE t,r2