Neo4j：如何将多个密码组合成一个？

我有一个Neo4j数据库，带有常用的社交图。我正在尝试创建一个活动提要（用户X跟踪了您，用户Y喜欢您的消息等）

有

用户

和

消息

节点

和

后面

，

喜欢

和

提到

关系，每个关系都在属性上创建了一个

（实际上，我还需要一些关系，但为了简单起见，我将其保留为3作为示例）

我试图返回活动事件列表，按日期分页和排序。每个活动都会有发生的日期、与之相关的用户和消息（如果适用）

我对每种活动类型/关系都有这样的功能，但我很难将它们组合成一个密码/响应

密码分别是

喜欢

MATCH (me:User {username:"matt"})-[:Owner]->(msg:Message)<-[likes:Likes]-(user:User) RETURN user, msg, likes.created_on ORDER BY likes.created_on LIMIT 25

MATCH (me:User {username:"matt"})<-[mentions:Mentions]-(msg:Message)-[:Owner]-(user:User) RETURN user, msg, mentions.created_on ORDER BY mentions.created_on LIMIT 25

但是我现在完全迷路了！这似乎根本没有返回任何结果

关于如何将上述密码组合成一个请求，您有什么建议/建议吗？
您可以使用union
这样您就可以得到所有结果
您可以使用union
这样你就能得到所有的结果
试试这样的方法

MATCH (me:User {username:"matt"})
OPTIONAL MATCH (me)-[:Owner]->(msg:Message)<-[likes:Likes]-(user:User) 
WHERE likes.created_on > x-days-ago
WITH me, msg, user, likes.created_on as created_on
ORDER BY created_on LIMIT 25
WITH me, collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[mentions:Mentions]-(msg:Message)-[:Owner]->(user:User) 
WITH me, msg, user, mentions.created_on as created_on, activities
ORDER BY created_on LIMIT 25
WITH me, activities + collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[follows:Follows]-(user:User) 
WITH me, msg, user, follows.created_on as created_on, activities
ORDER BY created_on LIMIT 25
UNWIND (activities + collect(distinct {user:user, created_on:created_on})) as activity
RETURN activity
ORDER BY activity.created_on LIMIT 25

MATCH（me:User{username:“matt”}）
可选匹配（me）-[：Owner]->（msg:Message）x-days-ago
对于我，msg，user，likes.created_on作为created_on
根据限额25创建的订单
与我一起，收集（不同的{user:user，created_on:created_on}）作为活动
可选匹配（me）（用户：用户）
与我一起，msg，user，提及.created_on作为created_on，activities
根据限额25创建的订单
对于我来说，活动+收集（不同的{user:user，created_on:created_on}）作为活动
可选匹配（me）尝试类似的操作

MATCH (me:User {username:"matt"})
OPTIONAL MATCH (me)-[:Owner]->(msg:Message)<-[likes:Likes]-(user:User) 
WHERE likes.created_on > x-days-ago
WITH me, msg, user, likes.created_on as created_on
ORDER BY created_on LIMIT 25
WITH me, collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[mentions:Mentions]-(msg:Message)-[:Owner]->(user:User) 
WITH me, msg, user, mentions.created_on as created_on, activities
ORDER BY created_on LIMIT 25
WITH me, activities + collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[follows:Follows]-(user:User) 
WITH me, msg, user, follows.created_on as created_on, activities
ORDER BY created_on LIMIT 25
UNWIND (activities + collect(distinct {user:user, created_on:created_on})) as activity
RETURN activity
ORDER BY activity.created_on LIMIT 25

MATCH（me:User{username:“matt”}）
可选匹配（me）-[：Owner]->（msg:Message）x-days-ago
对于我，msg，user，likes.created_on作为created_on
根据限额25创建的订单
与我一起，收集（不同的{user:user，created_on:created_on}）作为活动
可选匹配（me）（用户：用户）
与我一起，msg，user，提及.created_on作为created_on，activities
根据限额25创建的订单
对于我来说，活动+收集（不同的{user:user，created_on:created_on}）作为活动
可选匹配（me）谢谢，我使用了UNION方法，但是限制和顺序应用于每个查询，而不是整个查询。显然，目前还不支持对联合查询应用总体限制（），但到目前为止……也许可以询问neo4j他们将实现它。或者在代码后处理hanks，我使用了UNION方法，但是限制和顺序应用于每个查询，而不是整个查询。显然，目前还不支持对联合查询应用总体限制（），但到目前为止……也许可以询问neo4j他们将实现它。或者以后用代码来做
MATCH (me:User {username:"matt"})
OPTIONAL MATCH (me)-[:Owner]->(msg:Message)<-[likes:Likes]-(user:User) 
WHERE likes.created_on > x-days-ago
WITH me, msg, user, likes.created_on as created_on
ORDER BY created_on LIMIT 25
WITH me, collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[mentions:Mentions]-(msg:Message)-[:Owner]->(user:User) 
WITH me, msg, user, mentions.created_on as created_on, activities
ORDER BY created_on LIMIT 25
WITH me, activities + collect(distinct {user:user, created_on:created_on}) as activities
OPTIONAL MATCH (me)<-[follows:Follows]-(user:User) 
WITH me, msg, user, follows.created_on as created_on, activities
ORDER BY created_on LIMIT 25
UNWIND (activities + collect(distinct {user:user, created_on:created_on})) as activity
RETURN activity
ORDER BY activity.created_on LIMIT 25