从neo4j中的通话记录生成网络图-新手

在Neo4J中，我试图将csv文件中的少量通话可视化（下面的假号码示例）：

我处理每一列（A，B），因为电话号码是节点，它们之间（A到B）的通话是关系

理想情况下，生成的图形应该显示多个对象之间的关系 节点（例如：值为1的节点将有三个到其他节点的连接，其中一个是值为2的节点2，该节点有另外三个连接，最后值为3的节点将有一个连接，但是分开的）

我正在尝试的代码

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
CREATE (A:phone {number: row.A})
CREATE (B:phone {number: row.B})
WITH A as a MATCH (a)-[:CALLED*]-(m)
RETURN a,m

很明显，它会产生重复的节点和没有二级箭头的单一关系

---

我做错了什么？

这应该是最有效的：

create constraint on (p:phone) assert p.number is unique;

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
with distinct row.A as value
MERGE (:phone {number: value});

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
with distinct row.B as value
MERGE (:phone {number: value});

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
MATCH (A:phone {number: row.A})
MATCH (B:phone {number: row.B})
MERGE (A)-[r:CALLED]->(B) 
  ON CREATE SET r.count = 1 
  ON MATCH SET r.count = r.count + 1;

但不确定您想要查询什么？ 例如

---

我想出来了。。。我尝试了这个匹配（a:phone）-[r:CALLED]->（b）返回a，b，sum（r.count）作为calls ORDER BY calls DESC LIMIT 10；它实际上提供了显示A方和B方的结果。我还尝试将（n）-[r:CALLED]->（b）与n，b匹配，将（r）计数为rel\u cnt，其中rel\u cnt>1返回n；要获得超过1个连接的连接…谢谢Michael，

create constraint on (p:phone) assert p.number is unique;

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
with distinct row.A as value
MERGE (:phone {number: value});

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
with distinct row.B as value
MERGE (:phone {number: value});

USING PERIODIC COMMIT
LOAD CSV WITH HEADERS FROM "file:blahblahblah.csv" AS row
MATCH (A:phone {number: row.A})
MATCH (B:phone {number: row.B})
MERGE (A)-[r:CALLED]->(B) 
  ON CREATE SET r.count = 1 
  ON MATCH SET r.count = r.count + 1;

MATCH (a:phone)-[r:CALLED]->(b)
RETURN a, sum(r.count) as calls
ORDER BY calls DESC LIMIT 10;