从查询结果neo4j创建新关系

我想从一个节点和一组节点之间最短路径的结果建立新的关系。我目前正在使用此查询执行此任务，但在两个节点之间，它运行得非常好：

MATCH
  (p1:Category {catName: "Main_topic_classifications"}), 
  (p2:Category {catName: "Monarchs_of_the_Bulgars"}),
  path = allShortestPaths((p2)-[:SUBCAT_OF*]->(p1))
UNWIND RELATIONSHIPS(path) AS rel
WITH STARTNODE(rel) AS s, ENDNODE(rel) AS e
MERGE (s)-[:NEW_SUBCAT]->(e)

如何对该查询进行泛化，以返回p2 Monars_of the_Bulgars和节点列表p1=[健康、历史、人性]之间的所有最短路径列表，而不是像上一个查询那样返回一个节点

感谢您的帮助。

这应该可以：

MATCH (p1:Category)
WHERE p1.category IN ["Health", "History", "Humanity"]
MATCH
  (p2:Category {catName: "Monarchs_of_the_Bulgars"}),
  path = allShortestPaths((p2)-[:SUBCAT_OF*]->(p1))
UNWIND RELATIONSHIPS(path) AS rel
WITH STARTNODE(rel) AS s, ENDNODE(rel) AS e
MERGE (s)-[:NEW_SUBCAT]->(e)

[更新]

如果p1还必须是Top_Main_分类的直接子类别，则可以执行以下操作：

MATCH (p1:Category)-[:SUBCAT_OF]->(main:Category {catName: "Main_topic_classifications"})
WHERE p1.category IN ["Health", "History", "Humanity"]
MERGE (p1)-[:NEW_SUBCAT]->(main)
MATCH
  (p2:Category {catName: "Monarchs_of_the_Bulgars"}),
  path = allShortestPaths((p2)-[:SUBCAT_OF*]->(p1))
UNWIND RELATIONSHIPS(path) AS rel
WITH STARTNODE(rel) AS s, ENDNODE(rel) AS e
MERGE (s)-[:NEW_SUBCAT]->(e)

---

谢谢你的帮助。我是否可以在返回的路径上再施加一个条件，在该路径中，顶级节点的运行状况、历史记录等必须连接到顶级主分类节点，即p1->top\u main\u classification？我修改了更新，以便在p1节点和主节点之间创建新的子类别关系。