Numpy 为什么它会出现；TypeError:图像数据的形状（20，）无效；

**当我在jupyter笔记本上用Python3执行上述代码时，我得到了一个类型错误，请大家用最简单的方式回答这个错误** 喜欢 TypeError回溯（最近一次调用上次） 在里面 ---->1 plt.imshow（m1）

---

当您调用

m1.重塑（4,5）

时，您不会将其赋给变量。该方法不会更改

m1

的形状，除非您将其重新指定给

m1

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\pyplot.py in imshow(X, cmap, norm, aspect, interpolation, alpha, vmin, vmax, origin, extent, shape, filternorm, filterrad, imlim, resample, url, data, **kwargs)
   2649         filternorm=filternorm, filterrad=filterrad, imlim=imlim,
   2650         resample=resample, url=url, **({"data": data} if data is not
-> 2651         None else {}), **kwargs)
   2652     sci(__ret)
   2653     return __ret

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\__init__.py in inner(ax, data, *args, **kwargs)
   1563     def inner(ax, *args, data=None, **kwargs):
   1564         if data is None:
-> 1565             return func(ax, *map(sanitize_sequence, args), **kwargs)
   1566 
   1567         bound = new_sig.bind(ax, *args, **kwargs)

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\cbook\deprecation.py in wrapper(*args, **kwargs)
    356                 f"%(removal)s.  If any parameter follows {name!r}, they "
    357                 f"should be pass as keyword, not positionally.")
--> 358         return func(*args, **kwargs)
    359 
    360     return wrapper

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\cbook\deprecation.py in wrapper(*args, **kwargs)
    356                 f"%(removal)s.  If any parameter follows {name!r}, they "
    357                 f"should be pass as keyword, not positionally.")
--> 358         return func(*args, **kwargs)
    359 
    360     return wrapper

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\axes\_axes.py in imshow(self, X, cmap, norm, aspect, interpolation, alpha, vmin, vmax, origin, extent, shape, filternorm, filterrad, imlim, resample, url, **kwargs)
   5613                               resample=resample, **kwargs)
   5614 
-> 5615         im.set_data(X)
   5616         im.set_alpha(alpha)
   5617         if im.get_clip_path() is None:

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\image.py in set_data(self, A)
    697                 or self._A.ndim == 3 and self._A.shape[-1] in [3, 4]):
    698             raise TypeError("Invalid shape {} for image data"
--> 699                             .format(self._A.shape))
    700 
    701         if self._A.ndim == 3:

TypeError: Invalid shape (20,) for image data

将numpy导入为np
将matplotlib.pyplot作为plt导入
#m1=np.random.randint（低=0，高=20，大小=（4,5））#这对你有帮助吗？
c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\pyplot.py in imshow(X, cmap, norm, aspect, interpolation, alpha, vmin, vmax, origin, extent, shape, filternorm, filterrad, imlim, resample, url, data, **kwargs)
   2649         filternorm=filternorm, filterrad=filterrad, imlim=imlim,
   2650         resample=resample, url=url, **({"data": data} if data is not
-> 2651         None else {}), **kwargs)
   2652     sci(__ret)
   2653     return __ret

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\__init__.py in inner(ax, data, *args, **kwargs)
   1563     def inner(ax, *args, data=None, **kwargs):
   1564         if data is None:
-> 1565             return func(ax, *map(sanitize_sequence, args), **kwargs)
   1566 
   1567         bound = new_sig.bind(ax, *args, **kwargs)

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\cbook\deprecation.py in wrapper(*args, **kwargs)
    356                 f"%(removal)s.  If any parameter follows {name!r}, they "
    357                 f"should be pass as keyword, not positionally.")
--> 358         return func(*args, **kwargs)
    359 
    360     return wrapper

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\cbook\deprecation.py in wrapper(*args, **kwargs)
    356                 f"%(removal)s.  If any parameter follows {name!r}, they "
    357                 f"should be pass as keyword, not positionally.")
--> 358         return func(*args, **kwargs)
    359 
    360     return wrapper

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\axes\_axes.py in imshow(self, X, cmap, norm, aspect, interpolation, alpha, vmin, vmax, origin, extent, shape, filternorm, filterrad, imlim, resample, url, **kwargs)
   5613                               resample=resample, **kwargs)
   5614 
-> 5615         im.set_data(X)
   5616         im.set_alpha(alpha)
   5617         if im.get_clip_path() is None:

c:\users\jaiprakash\appdata\local\programs\python\python37-32\lib\site-packages\matplotlib\image.py in set_data(self, A)
    697                 or self._A.ndim == 3 and self._A.shape[-1] in [3, 4]):
    698             raise TypeError("Invalid shape {} for image data"
--> 699                             .format(self._A.shape))
    700 
    701         if self._A.ndim == 3:

TypeError: Invalid shape (20,) for image data

import numpy as np
import matplotlib.pyplot as plt

#m1=np.random.randint(low=0, high=20, size=(4,5)) # << personally I would have done this & not bothered with the reshape

m1 = np.random.randint(0,20,4*5)
m1 = m1.reshape(4, 5)
plt.imshow(m1)