Objective c 目标C中的Sqlite数据库插入语句

我尝试只在sqlite数据库中插入两个整数变量。我创建了一个名为ups.sqlite的数据库，它有一个表（upstable），该表有两列。但当我打开/Users/ds/Library/Application Support/iPhone Simulator/5.0/Applications/fcb455-4B7F-4C47-81B6-AC4121874596/SqliteDeneme.app/ups.sqlite时，ups.sqlite中没有数据。我的代码在这里：

- (IBAction)buttonClick:(id)sender {

NSFileManager *fileManager = [NSFileManager defaultManager];
NSError *error;
NSString *dbPath = [self getDBPath];
BOOL success = [fileManager fileExistsAtPath:dbPath]; 

if(!success) {

    NSString *defaultDBPath = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"ups.sqlite"];
    success = [fileManager copyItemAtPath:defaultDBPath toPath:dbPath error:&error];

    if (!success) 
        NSAssert1(0, @"Failed to create writable database file with message '%@'.", [error localizedDescription]);
}   

NSLog(@"database path %@",dbPath);


if(!(sqlite3_open([dbPath UTF8String], &cruddb) == SQLITE_OK))
{
    NSLog(@"An error has occured.");
}

if(sqlite3_open([dbPath UTF8String], &cruddb) ==SQLITE_OK){

    NSString *  str1 =@"1";
    NSString * str2 =@"1";


    const char *sql = "INSERT INTO upssTable (column1, column2) VALUES (?,?)"; 

    NSInteger result = sqlite3_prepare_v2(cruddb,sql, -1, &stmt, NULL);
    NSLog(@"upss %s\n", sqlite3_errmsg(cruddb));

    if(result == SQLITE_OK)        
    {
        sqlite3_bind_int(stmt, 1, [str1 integerValue]);
        sqlite3_bind_int(stmt, 2, [str2 integerValue]);

    }
    else
    {
        NSAssert1(0, @"Error . '%s'", sqlite3_errmsg(cruddb));                        
    }
    sqlite3_reset(stmt);
    sqlite3_finalize(stmt);
    sqlite3_close(cruddb);
}
}

- (NSString *) getDBPath {

NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory , NSUserDomainMask, YES);
NSString *documentsDir = [paths objectAtIndex:0];
return [documentsDir stringByAppendingPathComponent:@"ups.sqlite"];
}

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我怎样才能解决这个问题？请帮帮我。谢谢你的回复

您正在创建sqlite3语句，但实际上并不是使用

sqlite3\u step（）

执行它

---

您似乎还要打开数据库两次？

您根本没有使用sqlite3\u step（）。这样试试

sqlite3 *database; 
 dbPath=[self.databasePath UTF8String];
    if(sqlite3_open(dbPath,&database)==SQLITE_OK)
    {
        const char *sqlstatement = "INSERT INTO upssTable (column1, column2) VALUES (?,?)"; 
        sqlite3_stmt *compiledstatement;

        if(sqlite3_prepare_v2(database,sqlstatement , -1, &compiledstatement, NULL)==SQLITE_OK)
        {
             NSString *  str1 =@"1";
    NSString * str2 =@"1";
      sqlite3_bind_int(compiledstatement, 1, [str1 integerValue]);
        sqlite3_bind_int(compiledstatement, 2, [str2 integerValue]);
         if(sqlite3_step(compiledstatement)==SQLITE_DONE)
            {
                NSLog(@"done");
            }
            else NSLog(@"ERROR");
            sqlite3_reset(compiledstatement);
    }
    else
    {
        NSAssert1(0, @"Error . '%s'", sqlite3_errmsg(cruddb));                        
    }
    sqlite3_close(database);
}

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罗布的解释很好。