Objective c 通过unicode循环到NSString

我试图找出如何循环使用unicode值并创建NSString。我已经想出了如何使用较短的代码：

    unichar buffer[26];
    unichar letter = 0x0041;
    for (int i = 0; i < 26; i++) {
        buffer[i] = letter;
        letter++;
    }
    NSLog(@"%@", [NSString stringWithCharacters: buffer length:26]);

得到3个表情符号

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我希望能够获得\u0001111和\U00022222之间所有unicode字符的字符串（随机示例）。这是我第一次和unicodes打交道，这完全让我难堪。任何代码片段或指针都将不胜感激。

并非U+11111和U+22222之间的所有值都在Unicode标准中定义 （比较），所以我采取 例如，不同的范围：

uint32_t first = 0x1F300;
uint32_t last  = 0x1F310;
NSMutableString *string = [NSMutableString string];
for (uint32_t unicode = first; unicode <= last; unicode++) {
    // Create a string from the (4 byte, little-endian) unicode value:
    NSString *tmp = [[NSString alloc] initWithBytes:&unicode length:4 encoding:NSUTF32LittleEndianStringEncoding];

    [string appendString:tmp];
}
NSLog(@"%@", string);

uint32\u t first=0x1F300；
uint32_t last=0x1F310；
NSMutableString*字符串=[NSMutableString]；
对于（uint32_t unicode=first；unicode
uint32_t first = 0x1F300;
uint32_t last  = 0x1F310;
NSMutableString *string = [NSMutableString string];
for (uint32_t unicode = first; unicode <= last; unicode++) {
    // Create a string from the (4 byte, little-endian) unicode value:
    NSString *tmp = [[NSString alloc] initWithBytes:&unicode length:4 encoding:NSUTF32LittleEndianStringEncoding];

    [string appendString:tmp];
}
NSLog(@"%@", string);