Objective c 根据NSMutable数组中的内容对NSMutableDictionary排序
我有一个数组Objective c 根据NSMutable数组中的内容对NSMutableDictionary排序,objective-c,cocoa,Objective C,Cocoa,我有一个数组NSMutableArray,其值为 10,2,13,4 还有NSMutableDictionary,其中的值是 (10,a)、(20,b)、(13,c)、(2,d)、(33,e) 我想对NSMutableDictionary中的值进行排序,使dict的结果应该是(10,a)、(2,d)、(13,c)我为您编写的函数。希望它能帮助您: - (void)removeUnnedful { NSMutableDictionary *dict = [[NSMutableDiction
NSMutableArray
,其值为
10,2,13,4
还有NSMutableDictionary
,其中的值是
(10,a)、(20,b)、(13,c)、(2,d)、(33,e)
我想对
NSMutableDictionary
中的值进行排序,使dict的结果应该是(10,a)、(2,d)、(13,c)我为您编写的函数。希望它能帮助您:
- (void)removeUnnedful
{
NSMutableDictionary *dict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:
@"a", [NSNumber numberWithInt:10],
@"b", [NSNumber numberWithInt:20],
@"c", [NSNumber numberWithInt:13],
@"d", [NSNumber numberWithInt:2 ],
@"e", [NSNumber numberWithInt:33],
nil];
NSMutableArray *array = [[NSMutableArray alloc] initWithObjects:
[NSNumber numberWithInt:10],
[NSNumber numberWithInt:2 ],
[NSNumber numberWithInt:13],
[NSNumber numberWithInt:14], nil];
NSMutableDictionary *newDict = [[NSMutableDictionary alloc] init];
for (NSNumber *key in [dict allKeys])
{
NSLog(@"%@", key);
if ([array containsObject:key])
{
[newDict setObject:[dict objectForKey:key] forKey:key];
}
}
for (NSNumber *key in [newDict allKeys])
NSLog(@"key: %@, value: %@", key, [newDict objectForKey:key]);
[dict release];
[array release];
}
未定义
NSDictionary
实例中键和值的排序顺序。(见)由于您已经拥有一个有序键数组,您可以简单地迭代该数组并访问该键的字典值:
NSMutableArray* sortedArray = [NSMutableArray arrayWithObjects:@"10", @"2", @"13", @"4", nil];
NSDictionary* dictionary = [NSDictionary dictionaryWithObjectsAndKeys:@"a", @"10", @"b", @"20", @"c", @"13", @"d", @"2", @"e", @"33" , nil];
NSMutableDictionary* filteredDictionary = [NSMutableDictionary dictionary];
for(id key in sortedArray)
{
id value = [dictionary objectForKey:key];
if(value != nil)
{
[filteredDictionary setObject:[dictionary objectForKey:key] forKey:key];
}
}
NSLog(@"%@", filteredDictionary);
请注意,
[NSDictionary description]
的默认实现按键对输出进行升序排序(对于类型为NSString
的键),但这只是一个表示-nsdictionary
没有定义的排序顺序,因此您不应该依赖于allkey
和allValues
的排序。是否要从dictionary中删除不在数组中的值?查看我的答案,希望对您有所帮助。