Objective c 设置弹出按钮的操作
我以编程方式创建了一个NSPoupButton,并为我的选择创建了一个数组,如何为每个单独的数组选择创建一个setAction?谢谢Objective c 设置弹出按钮的操作,objective-c,xcode,cocoa,nspopupbutton,Objective C,Xcode,Cocoa,Nspopupbutton,我以编程方式创建了一个NSPoupButton,并为我的选择创建了一个数组,如何为每个单独的数组选择创建一个setAction?谢谢 NSRect buttonRect = NSMakeRect(1705, 145, 78, 50); //Button Array. When I pick the choice it closes the diologue box NSArray *newArray; NSString *color1 = @"Blue Color"
NSRect buttonRect = NSMakeRect(1705, 145, 78, 50);
//Button Array. When I pick the choice it closes the diologue box
NSArray *newArray;
NSString *color1 = @"Blue Color";
NSString *color2 = @"Green Color";
NSString *color3 = @"Clear Color";
newArray = [NSArray arrayWithObjects: color1, color2, color3, nil];
NSPopUpButton *button = [[NSPopUpButton alloc] initWithFrame:buttonRect pullsDown:YES];
[self addSubview:button];
[button addItemsWithTitles:newArray];
//want my action for each individual string
[button setAction:@selector(changeFilterColor)];
-(void) changeFilterColor
{
NSLog(@"colorChanged");
}
您需要将协议添加到接口(.h文件):
创建nspoupbutton
后。另外,使用setAction:
删除该行
复制此委托方法:
-(void)menu:(NSMenu *)menu willHighlightItem:(NSMenuItem *)item
{
if ([item.title isEqualToString:@"Blue Color"]) { ... } //etc
}
添加必要的if语句以完成比较。另一个选项是使用最初在代码中使用的
setAction
方法。但对于选择调用的选择器,请将其设置为接收发送方对象。大概是这样的:
-(void)method:(NSMenuItem *)sender
然后,您可以验证发送者对象是否有效,并从中获取标题。我有点担心使用
NSMenuDelegate
进行此操作。我应该在协议中添加什么?-(无效)菜单:
?看起来您缺少一个[按钮setTarget:self]
-(void)menu:(NSMenu *)menu willHighlightItem:(NSMenuItem *)item
{
if ([item.title isEqualToString:@"Blue Color"]) { ... } //etc
}
-(void)method:(NSMenuItem *)sender