选择大于ORACLE
我尝试了以下语句的不同变体,结果是它必须做的事情的一半,我不知道缺少了什么选择大于ORACLE,oracle,Oracle,我尝试了以下语句的不同变体,结果是它必须做的事情的一半,我不知道缺少了什么 SELECT DISTINCT COUNT(*) AS NO_RESERVATIONS, HG.RESV_ID, HR.BOOKING_CUS_ID AS BOOKED_BY, C.CUS_NAME FROM HOLIDAY_RESERVATION HR INNER JOIN(HOLIDAY_GROUP HG INNER JOIN CUSTOMER C ON HG.CUS_ID = C.CUS_ID) ON HR.BOO
SELECT DISTINCT COUNT(*) AS NO_RESERVATIONS, HG.RESV_ID, HR.BOOKING_CUS_ID AS BOOKED_BY, C.CUS_NAME
FROM HOLIDAY_RESERVATION HR INNER JOIN(HOLIDAY_GROUP HG INNER JOIN CUSTOMER C
ON HG.CUS_ID = C.CUS_ID)
ON HR.BOOKING_CUS_ID = HG.CUS_ID
WHERE HR.RESV_ID >= 2
GROUP BY HG.RESV_ID, HR.BOOKING_CUS_ID, C.CUS_NAME;
收益率
NO_RESERVATIONS RESV_ID BOOKED_BY CUS_NAME
--------------- ---------- ---------- --------------------
1 3 5 Beatrice P. Rosa
1 8 15 Phillip B. Fleming
1 7 13 Debra V. Key
1 4 7 Magee A. Pace
2 11 3 Hadassah T. Hebert
1 5 9 Portia D. Melton
2 2 3 Hadassah T. Hebert
1 6 11 Larissa X. Boyer
1 9 17 Wayne F. Burnett
1 10 19 Eleanor J. Padilla
10 rows selected.
它应该只显示做出两次或两次以上保留的人,在本例中是Hadassah T.Hebert
回答谢谢布莱恩的帮助
屈服
要筛选出分组结果,需要使用HAVING语句。因此,对于您的示例,您的查询如下所示:
SELECT DISTINCT COUNT(*) AS NO_RESERVATIONS, HG.RESV_ID, HR.BOOKING_CUS_ID AS BOOKED_BY, C.CUS_NAME
FROM HOLIDAY_RESERVATION HR INNER JOIN(HOLIDAY_GROUP HG INNER JOIN CUSTOMER C
ON HG.CUS_ID = C.CUS_ID)
ON HR.BOOKING_CUS_ID = HG.CUS_ID
WHERE HR.RESV_ID >= 2
GROUP BY HG.RESV_ID, HR.BOOKING_CUS_ID, C.CUS_NAME
HAVING count(*) > 1;
要筛选出分组结果,需要使用HAVING语句。因此,对于您的示例,您的查询如下所示:
SELECT DISTINCT COUNT(*) AS NO_RESERVATIONS, HG.RESV_ID, HR.BOOKING_CUS_ID AS BOOKED_BY, C.CUS_NAME
FROM HOLIDAY_RESERVATION HR INNER JOIN(HOLIDAY_GROUP HG INNER JOIN CUSTOMER C
ON HG.CUS_ID = C.CUS_ID)
ON HR.BOOKING_CUS_ID = HG.CUS_ID
WHERE HR.RESV_ID >= 2
GROUP BY HG.RESV_ID, HR.BOOKING_CUS_ID, C.CUS_NAME
HAVING count(*) > 1;
非常感谢,我永远不会忘记这个:)非常感谢,我永远不会忘记这个:)
SELECT DISTINCT COUNT(*) AS NO_RESERVATIONS, HG.RESV_ID, HR.BOOKING_CUS_ID AS BOOKED_BY, C.CUS_NAME
FROM HOLIDAY_RESERVATION HR INNER JOIN(HOLIDAY_GROUP HG INNER JOIN CUSTOMER C
ON HG.CUS_ID = C.CUS_ID)
ON HR.BOOKING_CUS_ID = HG.CUS_ID
WHERE HR.RESV_ID >= 2
GROUP BY HG.RESV_ID, HR.BOOKING_CUS_ID, C.CUS_NAME
HAVING count(*) > 1;