Oracle sql中的rownum与group by

我需要构建一个查询，以按成员检索信息组和过期日期，但我需要每个成员都有一个序列号

例如：

如果成员A有3条记录要过期，B只有1条，C有2条，我需要这样的结果：

Number Member ExpDate 1 A 01/01/2020 2 A 02/01/2020 3 A 03/01/2020 1 B 01/01/2020 1 C 01/01/2020 2 C 02/01/2020 我现在的问题是：

SELECT ROW_NUMBER() OVER(ORDER BY TRUNC(EXPIRATION_DT) ASC) AS SEQUENCE, MEMBER_ID AS MEMBER, SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) AS POINTS, trunc(EXPIRATION_DT) AS EXPDATE
FROM TABLE1
WHERE EXPIRATION_DT > SYSDATE AND  EXPIRATION_DT < SYSDATE + 90
GROUP BY MEMBER_ID, TRUNC(EXPIRATION_DT)
HAVING SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) > 0
ORDER BY 4 ASC;

但是我不能把序列号分组。。。。现在的结果是：

Seq Mem Points Date 1 1-O 188 2018-03-01 00:00:00 2 1-C 472 2018-03-01 00:00:00 3 1-A 485 2018-03-01 00:00:00 4 1-1 267 2018-03-01 00:00:00 5 1-E 500 2018-03-01 00:00:00 6 1-P 55 2018-03-01 00:00:00 7 1-E 14 2018-03-01 00:00:00

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我想你需要一个稠密的_秩窗口函数。试试这个-

 SELECT DENSE_RANK() OVER (PARTITION BY MEMBER ORDER BY TRUNC(EXPIRATION_DT) ASC) AS SEQUENCE
       ,MEMBER_ID AS MEMBER
       ,SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) AS POINTS
       ,trunc(EXPIRATION_DT) AS EXPDATE
FROM TABLE1
WHERE EXPIRATION_DT > SYSDATE AND  EXPIRATION_DT < SYSDATE + 90
GROUP BY MEMBER_ID
        ,TRUNC(EXPIRATION_DT)
HAVING SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) > 0
ORDER BY 4 ASC;

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我想你需要一个稠密的_秩窗口函数。试试这个-

 SELECT DENSE_RANK() OVER (PARTITION BY MEMBER ORDER BY TRUNC(EXPIRATION_DT) ASC) AS SEQUENCE
       ,MEMBER_ID AS MEMBER
       ,SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) AS POINTS
       ,trunc(EXPIRATION_DT) AS EXPDATE
FROM TABLE1
WHERE EXPIRATION_DT > SYSDATE AND  EXPIRATION_DT < SYSDATE + 90
GROUP BY MEMBER_ID
        ,TRUNC(EXPIRATION_DT)
HAVING SUM(ACCRUALED_VALUE) - SUM(USED_VALUE) > 0
ORDER BY 4 ASC;

此选择返回第一列的序列号

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这个选择返回序列号为的第一列

您能解释一下，您的实际结果中的列Mem是什么，以及如何将其转换为A、B、C？A、B或C只是可能值的示例…您能解释一下，您的实际结果中的列Mem是什么，以及如何将其转换为A、B、C？A，B或C只是可能值的示例。。。