Pandas 基于值的索引对序列行重新排序

我有一个大熊猫系列，所以优化是关键

pd.Series(['I like apples', 'They went skiing vacation', 'Apples are tasty', 'The skiing was great'], dtype='string')

0                I like apples
1    They went skiing vacation
2             Apples are tasty
3         The skiing was great
dtype: string

假设这些行是字符串列表，即第0行是['i'，'like'，'apples']

我想获取say'apples'的索引，并根据该索引的值对行进行重新排序。在本例中，该系列类似于：

2             Apples are tasty
0                I like apples
1    They went skiing vacation
3         The skiing was great
dtype: string

因为第2行中“apples”（忽略大小写敏感度）的索引为0。

使用

列表理解和列举的另一个想法：

a = [next(iter(i for i, j in enumerate(x.split()) if j.lower() == 'apples'), len(s)*10) for x in s]
print (a)
[2, 40, 0, 40]

s = s.loc[np.array(a).argsort()]
print (s)
2             Apples are tasty
0                I like apples
1    They went skiing vacation
3         The skiing was great
dtype: string

---

抱歉，耶兹雷尔，我的问题不清楚。行由字符串列表组成。（我相应地编辑了我的问题）len（s）*10的原因是什么？@user270199为了正确的顺序，我需要一些大数字，而不是最大整数，我使用这个技巧

a = [next(iter(i for i, j in enumerate(x.split()) if j.lower() == 'apples'), len(s)*10) for x in s]
print (a)
[2, 40, 0, 40]

s = s.loc[np.array(a).argsort()]
print (s)
2             Apples are tasty
0                I like apples
1    They went skiing vacation
3         The skiing was great
dtype: string