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Perl变量垃圾收集和refcount_Perl - Fatal编程技术网

Perl变量垃圾收集和refcount

Perl变量垃圾收集和refcount,perl,Perl,在以下示例中,我对Perl中的变量垃圾收集有点困惑: #!/bin/env perl use v5.14; package MyTestModule { sub foo { my $fh = shift; for(1..100){ say "PUT"; $fh->autoflush(1); print $fh "Heloo\n"; sleep 1; } } } package main; use

在以下示例中,我对Perl中的变量垃圾收集有点困惑:

#!/bin/env perl
use v5.14;

package MyTestModule {
sub foo {
    my $fh = shift;
    for(1..100){
        say "PUT";
        $fh->autoflush(1);
        print $fh "Heloo\n";
        sleep 1;
    }
}
}


package main;

use AnyEvent;
use AnyEvent::Fork::Template;

my $cv = AnyEvent->condvar;
$AnyEvent::Fork::Template->fork->run("MyTestModule::foo", sub {
    my $fh_fh_fh = shift;
    my $w_w_w;
    $w_w_w = AnyEvent->io(fh => $fh_fh_fh, poll => "r", cb => sub {
           $w_w_w unless 1;
           sysread $fh_fh_fh, my $rslt, 10;
           say "GOT:", $rslt;
            }
        );
   });
$cv->wait;
在上面的代码中,如果我删除
$w_w_w
,那么由于
AnyEvent->io
创建了一个对象,它的引用变为零,那么它将被Perl回收,这使得代码无法工作(不会调用cb)

然后我将其分配给标量
$w\u w\u w
,但我不需要回调中的
$w\u w\u w
。但以下代码不起作用(将不调用回调):

因此,我在回调中添加了一行代码(您可以在这个请求的前面看到):

$w\u w\w,除非1

因为断言总是错误的,所以它不会运行,我认为perl编译器/解释器会优化这行代码(删除它),那么$w_w_w的引用计数将为零。并且也不会调用回调。 但它是有效的。因此,我希望有人能解释这一点

perl-MO=Deparse t2.pl

sub BEGIN {
    require v5.14;
}
package MyTestModule;
sub foo {
    use strict;
    no feature;
    use feature ':5.12';
    my $fh = shift();
    foreach $_ (1 .. 100) {
        say 'PUT';
        $fh->autoflush(1);
        print $fh "Heloo\n";
        sleep 1;
    }
}
package main;
use strict;
no feature;
use feature ':5.12';
{;};
use AnyEvent;
use AnyEvent::Fork::Template;
my $cv = 'AnyEvent'->condvar;
$AnyEvent::Fork::Template->fork->run('MyTestModule::foo', sub {
    my $fh_fh_fh = shift();
    my $w_w_w;
    $w_w_w = 'AnyEvent'->io('fh', $fh_fh_fh, 'poll', 'r', 'cb', sub {
        '???';
        sysread $fh_fh_fh, my $rslt, 10;
        say 'GOT:', $rslt;
    }
    );
}
);
$cv->wait;

我在perlmonks.org上找到了答案:

你把我的$fh\u fh\u fh转换成了什么值??它是socketpair的一个文件处理程序,用于与forked进程进行通信。既然你不在乎$w\u w,那么在回调子项的末尾添加
undef$w\u w\u w
,而不是
$w\u w\u,除非1
-我想,因为你至少是reference在anonymous sub中添加$w_w_w_w,引用使其通过编译时,不会被破坏。但不是100%确定,因此不想将此作为答案发布。请注意,代码泄漏给观察者-永远无法再次破坏观察者。如果观察者被认为是永恒的,那么这很好。在perl模块中,这是最有可能的不想要的行为。
$AnyEvent::Fork::Template->fork->run("MyTestModule::foo", sub {
    my $fh_fh_fh = shift;
    my $w_w_w;
    $w_w_w = AnyEvent->io(fh => $fh_fh_fh, poll => "r", cb => sub {

       sysread $fh_fh_fh, my $rslt, 10;
            say "GOT:", $rslt;
        }
    );
  });
sub BEGIN {
    require v5.14;
}
package MyTestModule;
sub foo {
    use strict;
    no feature;
    use feature ':5.12';
    my $fh = shift();
    foreach $_ (1 .. 100) {
        say 'PUT';
        $fh->autoflush(1);
        print $fh "Heloo\n";
        sleep 1;
    }
}
package main;
use strict;
no feature;
use feature ':5.12';
{;};
use AnyEvent;
use AnyEvent::Fork::Template;
my $cv = 'AnyEvent'->condvar;
$AnyEvent::Fork::Template->fork->run('MyTestModule::foo', sub {
    my $fh_fh_fh = shift();
    my $w_w_w;
    $w_w_w = 'AnyEvent'->io('fh', $fh_fh_fh, 'poll', 'r', 'cb', sub {
        '???';
        sysread $fh_fh_fh, my $rslt, 10;
        say 'GOT:', $rslt;
    }
    );
}
);
$cv->wait;