如何使用克隆保留嵌套Perl哈希的插入顺序？

我使用IxHash来记住哈希的插入顺序。但是当使用克隆来复制散列时，我得到了一个空散列

use strict;
use Switch;
use Data::Dumper;
use Clone qw(clone);
use Tie::Autotie 'Tie::IxHash';

our %h_basic_values;
my $t = tie our(%h_inner_hash), "Tie::IxHash";
my $t1 = tie our(%h_inner_hash1) , "Tie::IxHash";

%h_inner_hash = (
'in_1' => 'val_1',
'in_2' => 'val_2',
'in_3' => 'val_3'
);

%h_inner_hash1 = (
'innnn_1' => 'vallll_1',
'innnn_2' => 'vallll_2',
'innnn_3' => 'vallll_3',
);

$h_inner_hash{in_4}{inn_1} = "vall_1";
$h_inner_hash{in_4}{inn_2} = "vall_2";
$h_inner_hash{in_4}{inn_3} = "vall_3";
$h_inner_hash{in_4}{inn_4} = "vall_4";
$h_inner_hash{in_4}{inn_5}{innn_1} = 'valll_1';
$h_inner_hash{in_4}{inn_5}{innn_2} = "valll_2";
$h_inner_hash{in_4}{inn_5}{innn_3} = "valll_3";
$h_inner_hash{in_4}{inn_5}{innn_4} = "valll_4";

$h_inner_hash{in_4}{inn_5}{innn_5} = clone(\%h_inner_hash1);
print Dumper(\%h_inner_hash);

---

在$h_inner_hash{in_4}{inn_5}{innn_5}中，我得到了一个空的hash。

克隆或

%h_inner_hash1

绑定这不是问题。这是一个好主意。从其perldoc：

use strict;
use Switch;
use Data::Dumper;
use Clone qw(clone);
use Tie::Autotie 'Tie::IxHash';

our %h_basic_values;
my $t = tie our(%h_inner_hash), "Tie::IxHash";
my $t1 = tie our(%h_inner_hash1) , "Tie::IxHash";

%h_inner_hash = (
'in_1' => 'val_1',
'in_2' => 'val_2',
'in_3' => 'val_3'
);

%h_inner_hash1 = (
'innnn_1' => 'vallll_1',
'innnn_2' => 'vallll_2',
'innnn_3' => 'vallll_3',
);

$h_inner_hash{in_4}{inn_1} = "vall_1";
$h_inner_hash{in_4}{inn_2} = "vall_2";
$h_inner_hash{in_4}{inn_3} = "vall_3";
$h_inner_hash{in_4}{inn_4} = "vall_4";
$h_inner_hash{in_4}{inn_5}{innn_1} = 'valll_1';
$h_inner_hash{in_4}{inn_5}{innn_2} = "valll_2";
$h_inner_hash{in_4}{inn_5}{innn_3} = "valll_3";
$h_inner_hash{in_4}{inn_5}{innn_4} = "valll_4";

$h_inner_hash{in_4}{inn_5}{innn_5} = clone(\%h_inner_hash1);
print Dumper(\%h_inner_hash);

漏洞 [……]

指定引用 在Tie:：IxHash示例中，您不能 做：

因为这会创建一个散列引用， 不是Tie:：IxHash的对象。这 散列引用最终被销毁 总之，用一个 Tie:：指向 空散列

use strict;
use Switch;
use Data::Dumper;
use Clone qw(clone);
use Tie::Autotie 'Tie::IxHash';

our %h_basic_values;
my $t = tie our(%h_inner_hash), "Tie::IxHash";
my $t1 = tie our(%h_inner_hash1) , "Tie::IxHash";

%h_inner_hash = (
'in_1' => 'val_1',
'in_2' => 'val_2',
'in_3' => 'val_3'
);

%h_inner_hash1 = (
'innnn_1' => 'vallll_1',
'innnn_2' => 'vallll_2',
'innnn_3' => 'vallll_3',
);

$h_inner_hash{in_4}{inn_1} = "vall_1";
$h_inner_hash{in_4}{inn_2} = "vall_2";
$h_inner_hash{in_4}{inn_3} = "vall_3";
$h_inner_hash{in_4}{inn_4} = "vall_4";
$h_inner_hash{in_4}{inn_5}{innn_1} = 'valll_1';
$h_inner_hash{in_4}{inn_5}{innn_2} = "valll_2";
$h_inner_hash{in_4}{inn_5}{innn_3} = "valll_3";
$h_inner_hash{in_4}{inn_5}{innn_4} = "valll_4";

$h_inner_hash{in_4}{inn_5}{innn_5} = clone(\%h_inner_hash1);
print Dumper(\%h_inner_hash);

作为一种手段，您可以手动逐键复制

%h\u inner\u hash1

：

$h_inner_hash{in_4}{inn_5}{innn_5}{$_} = $h_inner_hash1{$_} for keys %h_inner_hash1;

---

或者，您可以手动将散列的每一层绑定到tie:：IxHash，而不是使用tie:：Autotie。

只是为了澄清，POD中引用的部分位于BUGS标题下。