Php 数组中特定变量的计数

我有一个带有startDate变量的数据数组-我如何返回带有date变量的对象总数，然后只打印数字

$date = Todays date

foreach ($results->data as $row) {

    $checkDate = $row->startDate;

    if(date('Y-m-d', strtotime($row->startDate)) == $date){

      Return total of date found
    }
}

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只要在找到计数器时增加它：

$date = '2019-02-20';
$total = 0;

foreach ($results->data as $row) {   
    if(date('Y-m-d', strtotime($row->startDate)) == $date){
        $total++;  // same as $total = $total + 1;
    }
}
echo "$date found $total times";

---

$total++在if？@abracadver中，你能举个例子吗？这样我就可以给你一些信任：）。计数总是让我困惑，但如果我遇到棘手的情况basic@JessMcKenzie递增一个计数器变量来计数是一项非常基本的编程任务。