Php 在最后一个字符之后和另一个字符之前进行分析
我有一个数组,看起来是这样的:Php 在最后一个字符之后和另一个字符之前进行分析,php,regex,parsing,substring,Php,Regex,Parsing,Substring,我有一个数组,看起来是这样的: array(7) [ 0 => "account_bad_rooms_view-1" (24) 1 => "account_view-2" (14) 2 => "admin_collector_view-5" (22) 3 => "admin_collector_edit-5" (22) 4 => "machine_service_item_edit-57" (28) 5 => "money_view-5
array(7) [
0 => "account_bad_rooms_view-1" (24)
1 => "account_view-2" (14)
2 => "admin_collector_view-5" (22)
3 => "admin_collector_edit-5" (22)
4 => "machine_service_item_edit-57" (28)
5 => "money_view-58" (13)
6 => "mu_edit-61" (10)
]
我需要得到的子字符串将只包含“edit”
或“view”
,所以我需要在最后一个下划线之后和破折号之前解析这个字符串。到目前为止,我有:
foreach ($permissionsArray as $selectId => $permissions) {
preg_match('~_(.*?)-~', $permissions, $output);
dump($output[1]);
}
这适用于只有一个下划线的字符串,因此结果是:
"bad_rooms_view"
"view"
"collector_view"
"collector_edit"
"service_item_edit"
"view"
"edit"
我怎样才能用简单的方法来做呢
_([^_]*)-
您可以改为使用此函数。这将不允许另一个
。
您可以使用函数获得输出,而不使用任何循环:
$array=array("account_bad_rooms_view-1", "account_view-2", "admin_collector_view-5",
"admin_collector_edit-5", "machine_service_item_edit-57", "money_view-58", "mu_edit-61");
$matches = preg_filter('/^.+?_([^-_]+)-.*$/', '$1', $array);
print_r($matches);
输出:
Array
(
[0] => view
[1] => view
[2] => view
[3] => edit
[4] => edit
[5] => view
[6] => edit
)
我也探讨过这一点,但是那些与模式不匹配的条目呢?它们将被跳过,我认为它们应该被保留。我想出了一个好主意。