Php 如果选择/下拉列表更改，Mysql更新

我正在建立一个相当简单的crud网站。我有三个全部基于的选择/下拉列表

这是我的密码：

<? 
include('../config.php'); 
if (isset($_GET['id']) ) { 
   $id = (int) $_GET['id']; 
   if (isset($_POST['submitted'])) { 
       foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); }
       $cselect1 = $_REQUEST['cselect1'];
       $cselect2 = $_REQUEST['cselect2'];
       $cselect3 = $_REQUEST['cselect3'];

       $query="SELECT cat FROM cat WHERE id='$cselect1'";
       $result = mysql_query ($query);
       while($catselect=mysql_fetch_array($result)){
       $catselect1 = $catselect['cat'];
       }
       $query="SELECT cat FROM cat WHERE id='$cselect2'";
       $result = mysql_query ($query);
       while($catselect=mysql_fetch_array($result)){
       $catselect2 = $catselect['cat'];
       }
       $query="SELECT cat FROM cat WHERE id='$cselect3'";
       $result = mysql_query ($query);
       while($catselect=mysql_fetch_array($result)){
       $catselect3 = $catselect['cat'];
       }
   $sql = "UPDATE `company` SET  `name` =  '{$_POST['name']}' ,  `phone` =  '{$_POST['phone']}' ,  `cat1` =  '$catselect1' ,  `cat2` =  '$catselect2' ,  `cat3` =  '$cselect3' ,  `zipcode` =  '{$_POST['zipcode']}' ,  `city` =  '{$_POST['city']}' ,  `address` =  '{$_POST['address']}' ,  `address2` =  '{$_POST['address2']}' ,  `website` =  '{$_POST['website']}' ,  `product1` =  '{$_POST['product1']}' ,  `product2` =  '{$_POST['product2']}' ,  `product3` =  '{$_POST['product3']}' ,  `product4` =  '{$_POST['product4']}' ,  `product5` =  '{$_POST['product5']}' ,  `product6` =  '{$_POST['product6']}' ,  `product7` =  '{$_POST['product7']}' ,  `subcat1` =  '{$_POST['sselect1']}' ,  `subcat2` =  '{$_POST['sselect2']}' ,  `subcat3` =  '{$_POST['sselect3']}'   WHERE `id` = '$id' "; 
   mysql_query($sql) or die(mysql_error());
   $sql = "UPDATE `company_secondary` SET  `company_description` =  '{$_POST['description']}' ,  `since` =  '{$_POST['since']}' ,  `smoking` =  '{$_POST['select3']}' ,  `delivery` =  '{$_POST['select5']}' ,  `alcohol` =  '{$_POST['select6']}' ,  `kids` =  '{$_POST['select1']}' ,  `wheelchair` =  '{$_POST['select2']}' ,  `twitter` =  '{$_POST['twitter']}' ,  `facebook` =  '{$_POST['facebook']}' ,  `youtube` =  '{$_POST['youtube']}' ,  `premium` =  '{$_POST['premium']}' ,  `creditcards` =  '{$_POST['select4']}' ,  `outdoor` =  '{$_POST['select7']}' ,  `featured` =  '{$_POST['featured']}' ,  `shortdesc` =  '{$_POST['shortdesc']}' WHERE company_id = '$id' "; 
   mysql_query($sql) or die(mysql_error());
   echo "Edited Row<br/>";
   echo "<a href='allbiz.php'>Back To Listing</a>"; 
  } 

  $row = mysql_fetch_array ( mysql_query("SELECT * FROM `company` WHERE `id` = '$id' "));

?>

”/>
电话：

第1类：

两种选择：

在处理POST数据之前，从数据库中获取当前信息。对于任何设置为0的POST值，将其更改为当前存储的值

或根据提交的值动态构建SQL更新查询，检查每个值是否未设置为0

$update_query = "";
foreach(Array('company_name', 'company_description', 'started') as $key) {
    if(isset($_POST[$key]) && $_POST[$key] !== 0) {
        if($update_query) {
            $update_query .= ", ";
        }
        $update_query .= "`{$key}`='". mysql_real_escape_string($_POST[$key]) ."'";
    }
}
if($update_query) {
    mysql_query("UPDATE `table` SET {$update_query} WHERE `id`='$id' LIMIT 1");
}

一个比另一个好吗？就个人而言，我倾向于选择第一个选项，但那只是因为它更适合我为这些页面设置代码结构的方式。我认为第二种方法是更好的，因为你不去接触那些你不想更新的领域。
$update_query = "";
foreach(Array('company_name', 'company_description', 'started') as $key) {
    if(isset($_POST[$key]) && $_POST[$key] !== 0) {
        if($update_query) {
            $update_query .= ", ";
        }
        $update_query .= "`{$key}`='". mysql_real_escape_string($_POST[$key]) ."'";
    }
}
if($update_query) {
    mysql_query("UPDATE `table` SET {$update_query} WHERE `id`='$id' LIMIT 1");
}