Php Laravel BACK PACK管理面板。匿名全局作用域使用

Laravel BACK PACK管理面板。我想使用匿名全局作用域。这是。我有两个表（用户、帐户和个人资料） 在下面的屏幕截图中，您可以在accounts\u profiles中看到我们有一列用户id

首先，让我解释一下。 我在用户模型中输入的代码

protected static function boot(){
    parent::boot();
    $userId = 1;
    static::addGlobalScope('users', function (Builder $builder) use ($userId) {
      return  $builder->where('users.id', $userId);
    });
}

protected static function boot(){
    parent::boot();
    $userId = 1;
    static::addGlobalScope('users', function (Builder $builder) use ($userId) {
      return  $builder->join("accounts_profiles_biz", 'users.id', '=', 'accounts_profiles_biz.user_id');
    });
}

这给了我管理面板中的记录（因为我只获取用户id“1”记录）

但现在我想连接两个表（用户、帐户和配置文件）。 我知道我们将在用户模型中编写查询

protected static function boot(){
    parent::boot();
    $userId = 1;
    static::addGlobalScope('users', function (Builder $builder) use ($userId) {
      return  $builder->where('users.id', $userId);
    });
}

protected static function boot(){
    parent::boot();
    $userId = 1;
    static::addGlobalScope('users', function (Builder $builder) use ($userId) {
      return  $builder->join("accounts_profiles_biz", 'users.id', '=', 'accounts_profiles_biz.user_id');
    });
}

但是我犯了这个错误

response_message: [
{
code: 9997,
message: "SQLSTATE[42702]: Ambiguous column: 7 ERROR: column reference "id" is ambiguous LINE 1: ...s"."id" = "accounts_profiles_biz"."user_id" where "id" = $1 ... ^ (SQL: select * from "users" inner join "accounts_profiles_biz" on "users"."id" = "accounts_profiles_biz"."user_id" where "id" = 1 and "users"."deleted_at" is null limit 1), File: D:\xampp\htdocs\laravel\vendor\laravel\framework\src\Illuminate\Database\Connection.php, Line: 669",

Exception Code: "SQLSTATE[42702]: Ambiguous column: 7 ERROR: column reference "id" is ambiguous LINE 1: ...s"."id" = "accounts_profiles_biz"."user_id" where "id" = $1 ... ^ (SQL: select * from "users" inner join "accounts_profiles_biz" on "users"."id" = "accounts_profiles_biz"."user_id" where "id" = 1 and "users"."deleted_at" is null limit 1)"
}
]

非常感谢你

select * from "users" inner join "accounts_profiles_biz" on "users"."id" = "accounts_profiles_biz"."user_id" where "id" = 1 and "users"."deleted_at" is null limit 1

[其中“id”=1]，此id不明确，请检查$builder

---

建议使用雄辩的ORM范围

如果这样尝试，您会得到什么

static:：addGlobalScope（'users'，function（Builder$Builder）use（$userId）{return$Builder->with（“accounts_profile_biz”）；}）异常代码：“调用模型[App\User]上未定义的关系[accounts\u profile\u biz]”产生该错误。@EncangCutbrayDid您为表
accounts\u profiles\u biz
创建模型请将您的用户模型共享到用户的模型名为“User”，账户的模型名为“accounts\u profilebiz”返回$builder->where（'users.id'，$userId）；但当我这样做时，它会给我正确的数据。但这在join中造成了问题。