如何将php数组构造成json
下面是wordpress短代码中php的简化版本。我如何从使用jquery的所有玩家那里得到名字 部分代码:如何将php数组构造成json,php,jquery,mysql,arrays,json,Php,Jquery,Mysql,Arrays,Json,下面是wordpress短代码中php的简化版本。我如何从使用jquery的所有玩家那里得到名字 部分代码: $profile_personal_info['id'] = $player->ID; $profile_personal_info['Firstname'] = $fname; $profile_personal_info['Lastname'] = $lname; $profile_details_stats['S'] = $playerS
$profile_personal_info['id'] = $player->ID;
$profile_personal_info['Firstname'] = $fname;
$profile_personal_info['Lastname'] = $lname;
$profile_details_stats['S'] = $playerShots;
$profile_details_stats['F'] = $playerFouls;
$personalInfo = array();
foreach ( $profile_personal_info as $key => $value ) {
$personalInfo[$key] = $value;
}
$playerStatistics = array();
foreach ( $profile_details_stats as $key => $value ) {
$playerStatistics[$key] = $value;
}
$response[$player->ID] = array_merge($personalInfo, $playerStatistics);
}
$response['player-'.$player->ID] = array_merge($personalInfo, $playerStatistics);
}
这是来自的输出
jQ.getJSON( "PATH_TO_PHP_FILE", function( data ) {
console.log(data);
}
player-151: Object
personal: Object
Firstname:"Jason"
Lastname:"Smith"
为了简洁起见,我简化了代码。通常,在PHP和任何语言中,您都不会“手工”破坏JSON。您只需让该语言(或您友好的邻居第三方库)为您完成这项工作。你给它一个数据结构,就会得到JSON。反之亦然 快速搜索将引导我进入此页面:
这是我要找的东西。也许这会在将来帮助别人
$response[$position][$fname.' '.$lname] = array_merge($personalInfo, $playerStatistics);
结果证明我的方向是对的。我只需要做一些调整