Php 如何制作幻灯片，从数据库中获取信息（图像、标题、内容）？

如何制作幻灯片，从网站php、html和css的数据库中获取信息（图像、标题、内容）

我想做一个幻灯片为最后十个职位（产品）或功能职位（产品）在标题网站。你怎么能做到这一点？谢谢

因此，在这个脚本幻灯片中，我想重播数据库中的源代码（图像、标题、描述），而不是表POST中的源代码

<a href="#" class="show">
    <img src="images/flowing-rock.jpg" alt="Flowing Rock" width="580" height="360" title="" alt="" rel="<h3>Flowing Rock</h3>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. "/>
</a>

<a href="#">
    <img src="images/grass-blades.jpg" alt="Grass Blades" width="580" height="360" title="" alt="" rel="<h3>Grass Blades</h3>Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. "/>
</a>

<a href="#">
    <img src="images/ladybug.jpg" alt="Ladybug" width="580" height="360" title="" alt="" rel="<h3>Ladybug</h3>Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur."/>
</a>

<a href="#">
    <img src="images/lightning.jpg" alt="Lightning" width="580" height="360" title="" alt="" rel="<h3>Lightning</h3>Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum."/>
</a>

<a href="#">
    <img src="images/lotus.jpg" alt="Lotus" width="580" height="360" title="" alt="" rel="<h3>Lotus</h3>Sed ut perspiciatis unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam, eaque ipsa quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt explicabo."/>
</a>

<a href="#">
    <img src="images/mojave.jpg" alt="Mojave" width="580" height="360" title="" alt="" rel="<h3>Mojave</h3>Nemo enim ipsam voluptatem quia voluptas sit aspernatur aut odit aut fugit, sed quia consequuntur magni dolores eos qui ratione voluptatem sequi nesciunt."/>
</a>

<a href="#">
    <img src="images/pier.jpg" alt="Pier" width="580" height="360" title="" alt="" rel="<h3>Pier</h3>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua."/>
</a>

<a href="#">
    <img src="images/sea-mist.jpg" alt="Sea Mist" width="580" height="360" title="" alt="" rel="<h3>Sea Mist</h3>Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat."/>
</a>

<a href="#">
    <img src="images/stones.jpg" alt="Stone" width="580" height="360" title="" alt="" rel="<h3>Stone</h3>Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur."/>
</a>

我希望发布非品味链接图像，编写php代码从数据库中获取图像，以及标题和内容，但我希望make（do{wile（））}只获取最后十个产品。

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嗯，您还没有提供有关数据库结构的任何详细信息。。。但是让我们来介绍一下基本知识

首先，您需要执行一个查询，该查询返回一个由10项组成的数组（作为数组）。然后您需要创建一个输出所有内容的循环

在MySQLi中，你会这样做

$objStmt = $this->objDb->prepare("
    SELECT image, imageAlt, imageTitle, imageRel FROM posts WHERE [some criteria is met];
");
$objStmt->bind_param([some params to bind]);

$objStmt->execute();
$objStmt->bind_result($image, $imageAlt, $imageTitle, $imageRel);

$arrItems = array();

while ($objRow = $objStmt->fetch()) {
    $arrItem = array();
    $arrItem['image'] = $image;
    $arrItem['imageAlt'] = $imageAlt;
    $arrItem['imageTitle'] = $imageTitle;
    $arrItem['imageRel'] = $imageRel;
    array_push($arrItems, $arrItem);
    unset($arrItem);
}

然后

    foreach ($arrItems as $arrItem) {
        printf('<a href="#" class="show"><img src="%s" alt="%s" width="580" height="360" title="%s" alt="" rel="%s"/></a>', $arrItem['image'], $arrItem['imageAlt'], $arrItem['imageTitle'], $arrItem['imageRel']);
    }

foreach（$arrItems作为$arrItem）{
printf（“”，$arrItem['image']，$arrItem['imageAlt']，$arrItem['imageTitle']，$arrItem['imageRel']）；
}