对PHP数组的JSON响应

我正在使用Echo Nest API寻找类似的艺术家。答复如下：

{"response": {"status": {"version": "4.2", "code": 0, "message": "Success"}, "artists": [{"name": "Audio Adrenaline", "id": "ARGEZ5E1187FB56F38"}, {"name": "Tree63", "id": "ARWKO2O1187B9B5FA7"}]}}

我如何才能将艺术家的结果放入阵列中？所以我以后可以像这样回显它们：

echo $artist[0];

这是你需要的

$artist = json_decode($json);

或作为关联数组

$artist = json_decode($json, true);

这是你需要的

$artist = json_decode($json);

或作为关联数组

$artist = json_decode($json, true);

只需将第二个参数设置为

TRUE

，即可使用

$str = '...';
$json = json_decode($str, TRUE);
$artist = $json['response']['artists'];    
//$artist = json_decode($str, TRUE)['response']['artists']; as of PHP 5.4

print_r($artist);

输出：

Array
(
    [0] => Array
        (
            [name] => Audio Adrenaline
            [id] => ARGEZ5E1187FB56F38
        )

    [1] => Array
        (
            [name] => Tree63
            [id] => ARWKO2O1187B9B5FA7
        )

)

您只需将第二个参数设置为

TRUE

$str = '...';
$json = json_decode($str, TRUE);
$artist = $json['response']['artists'];    
//$artist = json_decode($str, TRUE)['response']['artists']; as of PHP 5.4

print_r($artist);

输出：

Array
(
    [0] => Array
        (
            [name] => Audio Adrenaline
            [id] => ARGEZ5E1187FB56F38
        )

    [1] => Array
        (
            [name] => Tree63
            [id] => ARWKO2O1187B9B5FA7
        )

)

---

使用

json\u解码

，找到

样本：

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

var_dump(json_decode($json));

输出：

object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

---

使用

json\u解码

，找到

样本：

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

var_dump(json_decode($json));

输出：

object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}